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A grass-lined trapezoidal channel has a bottom width of 40.0 ft with 4H:1V side slopes. The channel has a longitudinal slope of 0.0005 and a water depth of 15.0 ft. Compute the discharge rate in the channel for a Manning's "n" value of 0.038.

A grass-lined trapezoidal channel has a bottom width of 40.0 ft with 4H:1V side slopes. The channel has a longitudinal slope of 0.0005 and a water depth of 15.0 ft. Compute the discharge rate in the channel for a Manning's "n" value of 0.038.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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There is no channel width given but here is an example of a similar problem solved.
A grass-lined trapezoidal channel has a bottom width of 40.0 ft with 4H:1V side slopes. The channel has a longitudinal slope of 0.0005 and a water depth of 15.0 ft. Compute the discharge rate in the channel for a Manning's "n" value of 0.038.
Transcribed Image Text:A grass-lined trapezoidal channel has a bottom width of 40.0 ft with 4H:1V side slopes. The channel has a longitudinal slope of 0.0005 and a water depth of 15.0 ft. Compute the discharge rate in the channel for a Manning's "n" value of 0.038.
Example: Gutter Flow Water is flowing in a gutter at a depth of 0.40 ft. The gutter has a Manning's n value of 0.017, a side slope of 20:1, and a longitudinal slope of 0.01. Determine the discharge rate in the gutter using both Manning's equation and the gutter flow equation. Estimate the error in using the gutter flow equation. A = SS 1.49 0.017 1.6 Cm SS n 3.2 Q =10(0.4)² = 1.6 ft² P = y(1 + V1 + SS²) = 0.4(1 + V1 + 400) = 8.01 ft 1.6 2/3 e (0.01)¹1/2=4.79 cfs 8.01 Sin Error 1.49 n AR2/351/2 1.49 20 0.017 3.2 0.04 4.79 (0.4)(0.01)¹/2 = 4.75 cfs X 100 -0.8%
Transcribed Image Text:Example: Gutter Flow Water is flowing in a gutter at a depth of 0.40 ft. The gutter has a Manning's n value of 0.017, a side slope of 20:1, and a longitudinal slope of 0.01. Determine the discharge rate in the gutter using both Manning's equation and the gutter flow equation. Estimate the error in using the gutter flow equation. A = SS 1.49 0.017 1.6 Cm SS n 3.2 Q =10(0.4)² = 1.6 ft² P = y(1 + V1 + SS²) = 0.4(1 + V1 + 400) = 8.01 ft 1.6 2/3 e (0.01)¹1/2=4.79 cfs 8.01 Sin Error 1.49 n AR2/351/2 1.49 20 0.017 3.2 0.04 4.79 (0.4)(0.01)¹/2 = 4.75 cfs X 100 -0.8%
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