A grass-lined trapezoidal channel has a bottom width of 40.0 ft with 4H:1V side slopes. The channel has a longitudinal slope of 0.0005 and a water depth of 15.0 ft. Compute the discharge rate in the channel for a Manning's "n" value of 0.038.
A grass-lined trapezoidal channel has a bottom width of 40.0 ft with 4H:1V side slopes. The channel has a longitudinal slope of 0.0005 and a water depth of 15.0 ft. Compute the discharge rate in the channel for a Manning's "n" value of 0.038.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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There is no channel width given but here is an example of a similar problem solved.
Transcribed Image Text:A grass-lined trapezoidal channel has a bottom width of 40.0 ft
with 4H:1V side slopes. The channel has a longitudinal slope of
0.0005 and a water depth of 15.0 ft. Compute the discharge rate
in the channel for a Manning's "n" value of 0.038.
Transcribed Image Text:Example: Gutter Flow
Water is flowing in a gutter at a depth of 0.40 ft. The gutter has a
Manning's n value of 0.017, a side slope of 20:1, and a longitudinal
slope of 0.01. Determine the discharge rate in the gutter using both
Manning's equation and the gutter flow equation. Estimate the error
in using the gutter flow equation.
A =
SS
1.49
0.017
1.6
Cm SS
n 3.2
Q
=10(0.4)² = 1.6 ft²
P = y(1 + V1 + SS²) = 0.4(1 + V1 + 400) = 8.01 ft
1.6 2/3
e
(0.01)¹1/2=4.79 cfs
8.01
Sin
Error
1.49
n
AR2/351/2
1.49 20
0.017 3.2
0.04
4.79
(0.4)(0.01)¹/2 = 4.75 cfs
X 100 -0.8%
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