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Q: 2: A process fluid is pumped from the bottom of one storage tank to the another using centrifugal pump. The pipe is carbon steel with e-0.046. From the tank to the pump inlet, the line is 25 m long and contains elbows and gate valve which is equivalent to 180 pipe diameter. From the pump outlet to the second storage tank the line is 180 m long and contains elbows, gate valves and flow control valve which is equivalent to 500 pipe diameter The maximum flow rate of liquid is 55 m/hr. The fluid level in the first tank is 4 m above the inlet of the pump. The feed point of the second tank is 10 m above the pump inlet. The operating pressure in the first tank is 1.08 bar and that of the second tank is 1.5 bar. The physical properties of the fluid are: density 900 kg/m² and viscosity 1.5 mNm's. Determine: (1)-The diameter of the section line. (2)-the NPSH of the pump if the vapor pressure of the fluid at pump section is 30 KN/m². (3)- The power of the pump if the efficiency of the pump equal to 70%. Note that the diameter of the section line equal to the diameter of the discharge line and assume that the same flow rate in the section and discharge.

Q: 2: A process fluid is pumped from the bottom of one storage tank to the another using centrifugal pump. The pipe is carbon steel with e-0.046. From the tank to the pump inlet, the line is 25 m long and contains elbows and gate valve which is equivalent to 180 pipe diameter. From the pump outlet to the second storage tank the line is 180 m long and contains elbows, gate valves and flow control valve which is equivalent to 500 pipe diameter The maximum flow rate of liquid is 55 m/hr. The fluid level in the first tank is 4 m above the inlet of the pump. The feed point of the second tank is 10 m above the pump inlet. The operating pressure in the first tank is 1.08 bar and that of the second tank is 1.5 bar. The physical properties of the fluid are: density 900 kg/m² and viscosity 1.5 mNm's. Determine: (1)-The diameter of the section line. (2)-the NPSH of the pump if the vapor pressure of the fluid at pump section is 30 KN/m². (3)- The power of the pump if the efficiency of the pump equal to 70%. Note that the diameter of the section line equal to the diameter of the discharge line and assume that the same flow rate in the section and discharge.

Solid Waste Engineering
Solid Waste Engineering
3rd Edition
ISBN:9781305635203
Author:Worrell, William A.
Publisher:Worrell, William A.
Chapter5: Separation Processes
Section: Chapter Questions
Problem 5.19P
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https://www.chegg.com/homework-help/questi ons-and-answers/q-2-process-fluid-pumped-bo ttom-one-storage-tank-another-using-centrifug al-pump-pipe-carbo-q69875027 Question another Q: 2: A process fluid is pumped from the bottom of one storage tank to the using centrifugal pump. The pipe is carbon steel with e=0.046. From the tank to the pump inlet, the line is 25 m long and contains elbows and gate valve which is equivalent to 180 pipe diameter. From the pump outlet to the second storage tank the line is 180 m long and contains elbows, gate valves and flow control valve which is equivalent to 500 pipe diameter The maximum flow rate of liquid is 55 m/hr. The fluid level in the first tank is 4 m above the inlet of the pump. The feed point of the second tank is 10 m above the pump inlet. The operating pressure in the first tank is 1.08 bar and that of the second tank is 1.5 bar. The physical properties of the fluid are: density 900 kg/ m² and viscosity 1.5 mNm's. Determine: (1)-The diameter of the section line. (2)- the NPSH of the pump if the vapor pressure of the fluid at pump section is 30 KN/m². (3)-The power of the pump if the efficiency of the pump equal to 70%. Note that the diameter of the section line equal to the diameter of the discharge line and assume that the same flow rate in the section and discharge. Answer (1) (8.2 ↑ 4m Pr Given data: Q = 55 m³/hr ; L₁ = 25 m 12= 180m h₁ = 4m = 55 3600 +J P1 = 1.08 bar ; 1 = 900 103/m² DE 0.0986 a fe= NPSH Relative roughes ; tet assume velocity of in the of the flexid = 2 m/sec; a renganable valuve. (please specify the Value of velocity If it is not this), O=AV = Q = B_D² XV ļ 2 (m³/sec) = BY DX 2 SVD I u Re 11.83 x 107 Page No. Date L₂ h₂=10m = 1-08 × 70-² LOFPRY gooxg.81 {=0.046-m Den 1 = 180 Dea2 = 500 P₂ = 1.5bar : μl = 1.5% 16 ³ N/m² So Ness' = 98.6mm 98-6 farming friction factor from the maddy's Diagram $=0.0025 length including micellamas lasse 11 = 25+ (180 x 98-6x13³3) = 42-748 12 = 180+ (500x98 6x10³) = 229.3 m P₂.² 900x 2x 0.0986 hf₁ = ufti v² 234 -hf1 = 0·8838 m -hf₂ = 48h²v² = 4x0·0025*229-3x 2² रिपर 234 2x9.81* 0.0386 -h6₂ = 4.7412 m = 1.18 X 105 = hf=h₂&hf₂ = 0·8838 +4.74 12- hf = 574915 m Pam -he-hes- Pr S Ps 14.000466 - 4*00025 × 42-748 x 2² 2x 3.81 0.0386 Hp = 16.506 m Pover p = 60 sda x Mp n (108-302x10² +4 -0.8698 Too X9.01 8.95m -(-4) - D 8838- 3000w 900x982 Page No Date Power souwubred if n = 0.70 the P₁ + V₁+y₁ + hp = P² +ve +4₂ + hfiths So 1.08 x10 + 4 + Hp = 1·5 x 10²5 + 10 + 0-3818 900x9.31 +4.57412 900x90L Hp = 11.5 - 1.082 × 105 +6+ 5.7495 700 ×9.82 P= 3180.64 world. P= 3.180 kw Power P = 900x9-81 x 55 x 16.506 07 3660
Transcribed Image Text:https://www.chegg.com/homework-help/questi ons-and-answers/q-2-process-fluid-pumped-bo ttom-one-storage-tank-another-using-centrifug al-pump-pipe-carbo-q69875027 Question another Q: 2: A process fluid is pumped from the bottom of one storage tank to the using centrifugal pump. The pipe is carbon steel with e=0.046. From the tank to the pump inlet, the line is 25 m long and contains elbows and gate valve which is equivalent to 180 pipe diameter. From the pump outlet to the second storage tank the line is 180 m long and contains elbows, gate valves and flow control valve which is equivalent to 500 pipe diameter The maximum flow rate of liquid is 55 m/hr. The fluid level in the first tank is 4 m above the inlet of the pump. The feed point of the second tank is 10 m above the pump inlet. The operating pressure in the first tank is 1.08 bar and that of the second tank is 1.5 bar. The physical properties of the fluid are: density 900 kg/ m² and viscosity 1.5 mNm's. Determine: (1)-The diameter of the section line. (2)- the NPSH of the pump if the vapor pressure of the fluid at pump section is 30 KN/m². (3)-The power of the pump if the efficiency of the pump equal to 70%. Note that the diameter of the section line equal to the diameter of the discharge line and assume that the same flow rate in the section and discharge. Answer (1) (8.2 ↑ 4m Pr Given data: Q = 55 m³/hr ; L₁ = 25 m 12= 180m h₁ = 4m = 55 3600 +J P1 = 1.08 bar ; 1 = 900 103/m² DE 0.0986 a fe= NPSH Relative roughes ; tet assume velocity of in the of the flexid = 2 m/sec; a renganable valuve. (please specify the Value of velocity If it is not this), O=AV = Q = B_D² XV ļ 2 (m³/sec) = BY DX 2 SVD I u Re 11.83 x 107 Page No. Date L₂ h₂=10m = 1-08 × 70-² LOFPRY gooxg.81 {=0.046-m Den 1 = 180 Dea2 = 500 P₂ = 1.5bar : μl = 1.5% 16 ³ N/m² So Ness' = 98.6mm 98-6 farming friction factor from the maddy's Diagram $=0.0025 length including micellamas lasse 11 = 25+ (180 x 98-6x13³3) = 42-748 12 = 180+ (500x98 6x10³) = 229.3 m P₂.² 900x 2x 0.0986 hf₁ = ufti v² 234 -hf1 = 0·8838 m -hf₂ = 48h²v² = 4x0·0025*229-3x 2² रिपर 234 2x9.81* 0.0386 -h6₂ = 4.7412 m = 1.18 X 105 = hf=h₂&hf₂ = 0·8838 +4.74 12- hf = 574915 m Pam -he-hes- Pr S Ps 14.000466 - 4*00025 × 42-748 x 2² 2x 3.81 0.0386 Hp = 16.506 m Pover p = 60 sda x Mp n (108-302x10² +4 -0.8698 Too X9.01 8.95m -(-4) - D 8838- 3000w 900x982 Page No Date Power souwubred if n = 0.70 the P₁ + V₁+y₁ + hp = P² +ve +4₂ + hfiths So 1.08 x10 + 4 + Hp = 1·5 x 10²5 + 10 + 0-3818 900x9.31 +4.57412 900x90L Hp = 11.5 - 1.082 × 105 +6+ 5.7495 700 ×9.82 P= 3180.64 world. P= 3.180 kw Power P = 900x9-81 x 55 x 16.506 07 3660
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