Pyramid Lake is on the Paiute Indian Reservation in Nevada. The lake is famous for cutthroat trout. Suppose a friend tells you that the average length of trout caught in Pyramid Lake is μ = 19 inches. However, a survey reported that of a random sample of 51 fish caught, the mean length was x = 18.6 inches, with estimated standard deviation s = 3.3 inches. Do these data indicate that the average length of a trout caught in Pyramid Lake is less than μ = 19 inches? Use α = 0.05. What is the value of the sample test statistic? (Round your answer to three decimal places.)Sketch the sampling distribution and show the area corresponding to the P-value. State the null and alternate hypotheses. H0: μ < 19 in; H1: μ = 19 in H0: μ = 19 in; H1: μ ≠ 19 in H0: μ > 19 in; H1: μ = 19 in H0: μ = 19 in; H1: μ < 19 in H0: μ = 19 in; H1: μ > 19 in What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. The Student's t, since the sample size is large and σ is known. The standard normal, since the sample size is large and σ is unknown. The standard normal, since the sample size is large and σ is known. The Student's t, since the sample size is large and σ is unknown. Estimate the P-value. P-value > 0.010 0.0010 < P-value < 0.010 0.250 < P-value < 0.0010 0.125 < P-value < 0.250 P-value < 0.125 Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level α? At the α = 0.05 level, we reject the null hypothesis and conclude the data are statistically significant. At the α = 0.05 level, we reject the null hypothesis and conclude the data are not statistically significant. At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are statistically significant. At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant. Interpret your conclusion in the context of the application. There is sufficient evidence at the 0.05 level to conclude that the average fish length is less than 19 inches. There is insufficient evidence at the 0.05 level to conclude that the average fish length is l
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
Pyramid Lake is on the Paiute Indian Reservation in Nevada. The lake is famous for cutthroat trout. Suppose a friend tells you that the average length of trout caught in Pyramid Lake is μ = 19 inches. However, a survey reported that of a random sample of 51 fish caught, the mean length was x = 18.6 inches, with estimated standard deviation s = 3.3 inches. Do these data indicate that the average length of a trout caught in Pyramid Lake is less than μ = 19 inches? Use α = 0.05. What is the value of the sample test statistic? (Round your answer to three decimal places.)Sketch the sampling distribution and show the area corresponding to the P-value.
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