puck of mass mp slides across a horizontal surface and collides with a stationary, nonuniform rod that is pivoted about its left end in three configurations, as shown. In each case, the puck travels with the same initial velocity vp and collides with the rod at time tc. In Case 1 the puck rebounds away from the rod, in Case
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A puck of mass mp slides across a horizontal surface and collides with a stationary, nonuniform rod that is pivoted about its left end in three configurations, as shown. In each case, the puck travels with the same initial velocity vp and collides with the rod at time tc. In Case 1 the puck rebounds away from the rod, in Case 2 the puck comes to rest after the collision with the rod, and in Case 3 the puck sticks to the rod. Frictional effects between the rod, puck, and floor, as well as frictional effects of the pivot, are small enough to be considered negligible.
Calculate the rotational kinetic energy of the ROD after the collision in case 3 occurs.
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- Please helpPlease do all unanswered partsA 8.58-g bullet is moving horizontally with a velocity of +366 m/s, where the sign + indicates that it is moving to the right (see part a of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part b. Note that both blocks are moving after the collision with the bullet. The mass of the first block is 1168 g, and its velocity is +0.625 m/s after the bullet passes through it. The mass of the second block is 1556 g. (a) What is the velocity of the second block after the bullet imbeds itself? (b) Find the ratio of the total kinetic energy after the collision to that before the collision. +366m/s Block 1 (a) Before collision +0.625m/s mblock 1=1168 (b) After collision (a) Vblock2= Number (b) KE after/KEbefore = Number Block 2 17 block 2 = 1556 Mbullet =8.58E i block 2 K Units Units
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