**Problem Description:**A bullet with a mass of 8.58 g is moving horizontally with a velocity of +366 m/s, where the sign + indicates that it is moving to the right. The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one. Both blocks move after the collision. The mass of the first block is 1168 g, and its velocity is +0.625 m/s after the bullet passes through it. The mass of the second block is 1556 g.**Questions:**(a) What is the velocity of the second block after the bullet embeds itself?(b) Find the ratio of the total kinetic energy after the collision to that before the collision.**Diagrams:**- **(a) Before collision:** - Bullet moving right at +366 m/s towards Block 1 and Block 2.- **(b) After collision:** - Block 1 moving right at +0.625 m/s. - Block 2 and the bullet are shown together, implying the bullet is embedded. Their combined mass is 1556 g + 8.58 g.**Calculations:**(a) \( v_{\text{block 2}} \): Enter the velocity value in the solution box.(b) \(\text{KE}_{\text{after}} / \text{KE}_{\text{before}}\): Enter the ratio value in the solution box.

Answered: Image /qna-images/answer/b7a31856-821b-4050-b14c-414ea6b155e8.jpg

A 8.58-g bullet is moving horizontally with a velocity of +366 m/s, where the sign + indicates that it is moving to the right (see part a of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part b. Note that both blocks are moving after the collision with the bullet. The mass of the first block is 1168 g, and its velocity is +0.625 m/s after the bullet passes through it. The mass of the second block is 1556 g. (a) What is the velocity of the second block after the bullet imbeds itself? (b) Find the ratio of the total kinetic energy after the collision to that before the collision. +366m/s Block 1 (a) Before collision +0.625m/s mblock 1=1168 Block 2 (b) After collision mblock 2=1556 mbullet 8.58 block 2 (a) Vblock2= Number i (b) KE after/KEbefore= Number i Units Units Ĉ

A 8.58-g bullet is moving horizontally with a velocity of +366 m/s, where the sign + indicates that it is moving to the right (see part a of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part b. Note that both blocks are moving after the collision with the bullet. The mass of the first block is 1168 g, and its velocity is +0.625 m/s after the bullet passes through it. The mass of the second block is 1556 g. (a) What is the velocity of the second block after the bullet imbeds itself? (b) Find the ratio of the total kinetic energy after the collision to that before the collision. +366m/s Block 1 (a) Before collision +0.625m/s mblock 1=1168 Block 2 (b) After collision mblock 2=1556 mbullet 8.58 block 2 (a) Vblock2= Number i (b) KE after/KEbefore= Number i Units Units Ĉ

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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