Pu-250KNPu-250KNdraw shear force and bending moment diagramand With all details ofthe solution attachedWu=25KN/m(include self weight)T-2.0m--3.0m 2.0m

I have made both diagrams clearly and solved the question step by step with each point calculation.

Answered: Pu-250KN Pu-250KN draw shear force and…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Q4/A/ The tension specimen contains has original length L. -100 mm as a result of the tension its length increasing to 120mm. Calculation the engineering and true strains?
How can I find the reactions, shear force and bending moment in this problem?
Please solve it quickly
5
a) Calculate the reaction forces in terms of F andtheta.b) Calculate the internal shear force and moment as a function of x using cuts and summingforces and moments in terms of F, L, andtheta.c) Calculate the shear force and moments by integration in terms of x, L, F andtheta.d) Assuming a rectangular cross section compute the average normal stress for the case F =10kNat 30° where b =0.04 m, h = 0.08 m, at the point x = L/4, L = 1 m at the centroid.e) With the cross section given above compute the average normal stress for the case F =10kN at30° at the point x = L/4, L = 1 m at each surface of the beam.f) Calculate the shear stress at the top and bottom surface, at the neutral axis and at x = 0.25 mand y = 0.02 m above the neutral axis.
Calculate the riveted joints, find its efficiency and draw a suitable sketch. Thickness of the plates – t, mm is 12 Width of the plates – b, mm is 150 Load – P, kN is 20 Note. Choose a suitable material, determine its tearing stress. Take permissible shearing stress - teta=0.7sigmat ; Permissible crushing stress - sigmac=1.5sigmat ;
Q7 For the bracket shown in the figure: > The moment of the force (1000N) about pin A is...... > The moment of the force (1000N) about pin B is...... The moment of the force (1000N) about pin C is. 600mm 1000 N 500mm 200mm 240 N.m CCW, 562 N.m CCW, 1099 N.m CCW 200 N.m CW, 468 N.m CW, 915 N.m CW 562 N.m CW, 1099 N.m CW, 240 N.m CW 468 N.m CW, 915 N.m CW, 200 N.m CW O GOOD LUCK! Eiminer Asst. Lecturer. Reem Al-Timimi Head of the Department Dr. Hussein Sadig
B) Two plates joined with straps and a single row of two rivets (or bolts). Rivets have a diameter of d=10 mm and all made of ductile steel having yield strengths in shear of ty = 160 MPa. What force (F) in kN can be transmitted across the joint based on rivet shear strength, take F.S=2 ? %3D Rivet diameter = 10 mm
Q-1 Compute the max load (P ) if the stress in steel 120 Mpa and in bronze 70 Мра steel bronze A= 300mm2 E=83 Gpa 900mm2 E=200 Gpa L=4m L=3m 3m 3m 1m In the fig three rivets of 25 mm diameter joins the plates that are each 130 mm wide .The shearsress in the rivet is 80 Mpa and the stresses in the bearing are 120 Mpa . Determine .a)The minimum thickness of each plate .b) the largest average tensile stress in the plate 25mm Ø 130 Q-3 Two solid shafts of different material are rigidly fastened together and attached to rigid supports as shown in fig .Compute the maximum shearing stress developed in the assembly 3 m 2 m aluminium G=83 Gpa steel G=28 Gpa 50 mm dia 25 mm dia T= 2 kN .m
Why used two equipment in shear force and bending moment experiment (one for ?S.F and the other to B.M)
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Pu-250KN Pu-250KN draw shear force and bending moment diagram and With all details ofthe solution attached Wu-25KN/m(include selt weight) F-2.0m-- -3.0m 2.0m-