330k 198k 132k N 16 in.- 12 in. 12 in. E = 29×10086 D = 1.07 in (bigger rod) D=107mind(570.618 in. rod) Determine the deformation of the steel rod shown under the given loads. SOLUTION: • Divide the rod into components at the load application points. • Apply a free-body analysis on each component to determine the internal force • Evaluate the total of the component deflections.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Problem 2
330k
198k
132k
N
-16 in.-
12 in.
12 in.
E = 29×10086sa
D = 1.07 in (bigger rod)
D=107ind 0.618 in.
rod)
Determine the
deformation of the steel
rod shown under the
given loads.
SOLUTION:
• Divide the rod into components at
the load application points.
Apply a free-body analysis on
each component to determine the
internal force
• Evaluate the total of the component
deflections.
2-3
Transcribed Image Text:Problem 2 330k 198k 132k N -16 in.- 12 in. 12 in. E = 29×10086sa D = 1.07 in (bigger rod) D=107ind 0.618 in. rod) Determine the deformation of the steel rod shown under the given loads. SOLUTION: • Divide the rod into components at the load application points. Apply a free-body analysis on each component to determine the internal force • Evaluate the total of the component deflections. 2-3
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