Provide an interpretation for the following SPSS output: A researcher wanted to test therelationship between number of fries eaten per week and number of vegetables eaten perweek by the sample.Number of times Number of timeseat fries pereat vegetablesweekper weekNumber of times eat fries per Pearson Correlation1-.067weekSig. (2-tailed).005N17501750Number of times eatPearson Correlation-.0671vegetables per weekSig. (2-tailed)N.00517501750**Correlation is significant at the 0.01 level (2-tailed).Edit View Insert Format Tools Table12pt v Paragraph<BIUA>

From the report, we can observe a Pearson Correlation of -0.067. This is a weak but negative…

Answered: Provide an interpretation for the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Listed below are amounts of bills for dinner and the amounts of the tips that were left. Construct a scatterplot, find the value of the linear correlation coefficient r, and find the P-value of r. Determine whether there is sufficient evidence to support a claim of linear correlation between the two variables. Use a significance level of a = 0.01. If everyone were to tip with the same percentage, what should be the value of r? Bill (dollars) Tip (dollars) 31.80 52.94 85.82 102.16 60.17 111.77 D 5.46 6.07 15.82 15.40 11.15 20.32 Construct a scatterplot. Choose the correct graph below. O A. O B. Oc. D. Q 25- 25- 25 0- 30 0- 30 Bill Amount ($) 0+ 30 Bill Amount (S) 0- 30 Bill Amount (S) 120 120 120 Bill Amount (S) 120 The linear correlation coefficient is r= 0.954 (Round to three decimal places as needed.) Determine the null and alternative hypotheses. Ho: p H,: P (Type integers or decimals. Do not round.) Tip Amount ($) ip Amount ($) Tip Amount ($) Tip Amount ($)
A study was done to look at the relationship between number of partners college students have had in their lifetimes and their GPAs. The results of the survey are shown below. Partners 7 8 6 1 6 6 4 GPA 1.4 1.5 1.4 3 2.3 1.5 2.9 Find the correlation coefficient: r=r= Round to 2 decimal places. The null and alternative hypotheses for correlation are:H0:H0: ? r ρ μ Incorrect == 0 Ha:Ha: ? r ρ μ Incorrect ≠≠ 0 Use a level of significance of α=0.05α=0.05 to state the conclusion of the hypothesis test in the context of the study. You may want to reference the 95% Critical Values of the Sample Correlation Coefficient. There is statistically insignificant evidence to conclude that there is a correlation between the number of partners students have had in their lifetimes and their GPA. Thus, the use of the regression line is not appropriate. There is statistically significant evidence to conclude that a student who has had more partners will have a lower GPA than a…
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A study of bone density on 5 random women at a hospital produced the following results. Age 37 45 49 57 65 Bone Density 350 340 335 325 320 step 1: Calculate the correlation coefficient, r. Round your answer to six decimal places. step 2: Calculate the correlation coefficient, r. Round to 3 decimal places. step 3: positive, negative, or no correlation
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Five students provided data regarding the number of hours they spent on studying (TimeStudy) and their GPA. The data are as follows. Answer the following questions. TimeStudy GPA Student 1 2.00 3.50 Student 2 4.00 3.70 Student 3 5.00 3.30 Student 4 3.00 2.60 Student 5 4.00 3.40 a) According to the SPSS table, what can you conclude regarding the correlation between TimeStudy and GPA? Report the conclusions in proper formats. b) By fitting a linear regression line to represent the relationship between TimeStudy and GPA, the regression line function is ??? = ?. ?? + ?. ?? × ?????????. See the figure Calculate (by hand) the SSresidual.

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