properties are below: We 28 x 10 N 28x 10 g mai Footer 10 ms8m 3m moist=19.5 kN/cubm Sand and gravel Y sat-19.6 kN/cub m 4 m y sat-19.4 IN/cub m Clay Sand and 1) Thickness of normally-consolidated clay = 4 meters 2) Water table is 3 meters deep 3) Sand and Gravel y moist=19.5 kN/cubic meter, y saturated= 19.6 kN/cubic meter 4) Soft Clay (OCR=1) a. Initial void ratio of clay layer (e o) = 0.81 b. y sat- 19.4 kN/cubic meter c. Compression Index of clay Cc = 0.62 d. Swell Index of clay Cs = 0.12
properties are below: We 28 x 10 N 28x 10 g mai Footer 10 ms8m 3m moist=19.5 kN/cubm Sand and gravel Y sat-19.6 kN/cub m 4 m y sat-19.4 IN/cub m Clay Sand and 1) Thickness of normally-consolidated clay = 4 meters 2) Water table is 3 meters deep 3) Sand and Gravel y moist=19.5 kN/cubic meter, y saturated= 19.6 kN/cubic meter 4) Soft Clay (OCR=1) a. Initial void ratio of clay layer (e o) = 0.81 b. y sat- 19.4 kN/cubic meter c. Compression Index of clay Cc = 0.62 d. Swell Index of clay Cs = 0.12
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Estimate the primary consolidation settlement of the clay in centimeters from a
28,000 kN load on an 8m by 10 m footing. The subsurface consists of a 10 meter
thick layer of sand and gravel overlying a 4 meter thick layer of normally-
consolidated clay (OCR=1). Assume sand and gravel layers do not settle. Below
the soft clay is sand and gravel. Water table is 3 meters deep. Subsurface
properties are below:
W= 28 x 10 N 28 10 g maris)
Footer 10 mBm
moist=19.5 kN/cubm
Water level
Sand and gravel
Y sat-19.6 kN/cub m
y sat-19.4 N/cub m
4 m
Clay
Sand and gavel
1) Thickness of normally-consolidated clay = 4 meters
2) Water table is 3 meters deep
3) Sand and Gravel
y moist=19.5 kN/cubic meter, y saturated= 19.6 kN/cubic meter
4) Soft Clay (OCR=1)
a. Initial void ratio of clay layer (e o) = 0.81
b. y sat= 19.4 kN/cubic meter
c. Compression Index of clay Cc=0.62
d. Swell Index of clay Cs = 0.12
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