Professor Jane Newman teaches an introductory calculus course. She wanted to test the belief that success in her course is affected by high school performance. She collected the randomly selected data listed below and ran an ANOVA test as shown below. The data in the "High School Record" table represents performance of the student in Jane's calculus class. Anova: Single Factor High School Record Good Fair Poor SUMMARY 90 80 60 Groups Count Sum Average Variance Good 437 87.4 23.8 86 70 60 Fair 484 69.14285714 117.1428571 88 61 55 Poor 6. 357 59.5 45.5 93 52 62 80 73 50 65 70 ANOVA 83 Source of Variation df MS P-value F crit Between Groups 2162.442857 1081.221429 15.81415676 0.000202214 3.68232034 Within Groups 1025.557143 15 68.37047619 Total 3188 17 If we set a at 0.05, what would we conclude about the ANOVA test? State the null and alternative hypotheses and result clearly. Give a reason for your result. YOU a) MUST REFERENCE THE CONTEXT OF THE PROBLEM.

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
icon
Related questions
Question
Question #8
ph b, nd c
Professor Jane Newman teaches an introductory calculus course. She wanted to test the belief
that success in her course is affected by high school performance. She collected the randomly
selected data listed below and ran an ANOVA test as shown below. The data in the "High School
Record" table represents performance of the student in Jane's calculus class.
Anova: Single Factor
High School Record
Good
Fair
Poor
SUMMARY
90
80
60
Groups
Count
Sum
Average
Variance
437
87.4
23.8
86
70
60
Good
Fair
7
484
69.14285714
117.1428571
88
61
55
Poor
6
357
59.5
45.5
93
52
62
80
73
50
65
70
ANOVA
83
Source of
Variation
df
MS
P-value
F crit
Between Groups
2162.442857
2
1081.221429
15.81415676
0.000202214
3.682320344
Within Groups
1025.557143
15
68.37047619
Total
3188
17
If we set a at 0.05, what would we conclude about the ANOVA test? State the null
and alternative hypotheses and result clearly. Give a reason for your result. YOU
a)
MUST REFERENCE THE CONTEXT OF THE PROBLEM.
Transcribed Image Text:Question #8 ph b, nd c Professor Jane Newman teaches an introductory calculus course. She wanted to test the belief that success in her course is affected by high school performance. She collected the randomly selected data listed below and ran an ANOVA test as shown below. The data in the "High School Record" table represents performance of the student in Jane's calculus class. Anova: Single Factor High School Record Good Fair Poor SUMMARY 90 80 60 Groups Count Sum Average Variance 437 87.4 23.8 86 70 60 Good Fair 7 484 69.14285714 117.1428571 88 61 55 Poor 6 357 59.5 45.5 93 52 62 80 73 50 65 70 ANOVA 83 Source of Variation df MS P-value F crit Between Groups 2162.442857 2 1081.221429 15.81415676 0.000202214 3.682320344 Within Groups 1025.557143 15 68.37047619 Total 3188 17 If we set a at 0.05, what would we conclude about the ANOVA test? State the null and alternative hypotheses and result clearly. Give a reason for your result. YOU a) MUST REFERENCE THE CONTEXT OF THE PROBLEM.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Similar questions
Recommended textbooks for you
A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
A First Course in Probability
A First Course in Probability
Probability
ISBN:
9780321794772
Author:
Sheldon Ross
Publisher:
PEARSON