Problem Like friction, drag force opposes the motion of a particle in a fluid; however, drag force depends on the particle's velocity. Find the expression for the particle's velocity v(x) as a function of position at any point x in a fluid whose drag force is expressed as Fdrag = kmv where k is a constant, m is the mass of the particle and v is its velocity. Assume that the particle is constrained to move in the x-axis only with an initial velocity vo Solution: The net force along the x-axis is: ZF- -F then: mv- m Since acceleration is the first time derivative of velocity a = dv/dt, mv = m We can eliminate time de by expressing, the velocity on the left side of the equation as v = dx/dt. Manipulating the variables and simplifying, we arrive at the following expression = -k "Isolating" the infinitesimal velocity dx and integrating with respect to dx, we arrive at the following: vo- which shows that velocity decreases in a linear manner.
Problem Like friction, drag force opposes the motion of a particle in a fluid; however, drag force depends on the particle's velocity. Find the expression for the particle's velocity v(x) as a function of position at any point x in a fluid whose drag force is expressed as Fdrag = kmv where k is a constant, m is the mass of the particle and v is its velocity. Assume that the particle is constrained to move in the x-axis only with an initial velocity vo Solution: The net force along the x-axis is: ZF- -F then: mv- m Since acceleration is the first time derivative of velocity a = dv/dt, mv = m We can eliminate time de by expressing, the velocity on the left side of the equation as v = dx/dt. Manipulating the variables and simplifying, we arrive at the following expression = -k "Isolating" the infinitesimal velocity dx and integrating with respect to dx, we arrive at the following: vo- which shows that velocity decreases in a linear manner.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![QUESTION 1
Problem
Like friction, drag force opposes the motion of a particle in a fluid; however, drag force depends on the particle's velocity. Find the expression for the particle's velocity v(x) as a function of position at any point x in a fluid whose
drag force is expressed as
Fdrag = kmv
where k is a constant, m is the mass of the particle and v is its velocity. Assume that the particle is constrained to move in the x-axis only with an initial velocity vo.
Solution:
The net force along the x-axis is:
EF = -F
then:
mv = m
Since acceleration is the first time derivative of velocity a = dv/dt,
mv = m
We can eliminate time dt by expressing, the velocity on the left side of the equation as v= dx/dt. Manipulating the variables and simplifying, we arrive at the following expression
= -k
"Isolating" the infinitesimal velocity dx and integrating with respect to dx, we arrive at the following:
= v -
which shows that velocity decreases in a linear manner.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd9dec54f-af25-41cd-a5ad-e675b93a3c93%2F9b457ae1-a34e-4daf-b98f-f3c9d5db14c2%2Fc103mii_processed.png&w=3840&q=75)
Transcribed Image Text:QUESTION 1
Problem
Like friction, drag force opposes the motion of a particle in a fluid; however, drag force depends on the particle's velocity. Find the expression for the particle's velocity v(x) as a function of position at any point x in a fluid whose
drag force is expressed as
Fdrag = kmv
where k is a constant, m is the mass of the particle and v is its velocity. Assume that the particle is constrained to move in the x-axis only with an initial velocity vo.
Solution:
The net force along the x-axis is:
EF = -F
then:
mv = m
Since acceleration is the first time derivative of velocity a = dv/dt,
mv = m
We can eliminate time dt by expressing, the velocity on the left side of the equation as v= dx/dt. Manipulating the variables and simplifying, we arrive at the following expression
= -k
"Isolating" the infinitesimal velocity dx and integrating with respect to dx, we arrive at the following:
= v -
which shows that velocity decreases in a linear manner.
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