m A box rests on top of a flat bed truck. The box has a mass of m = 20 kg. The coefficient of static friction between the box and truck is u, = 0.81 and the coefficient of kinetic friction between the box and truck is u = 0.62. 1) The truck accelerates from rest to v; = 16 m/s in t = 12 s (which is slow enough that the bax will not slide). What is the acceleration of the box? m/s Submit You currently have O submissions for this question. Only 5 submission are allowed. You can make 5 more submissions for this question.

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A box rests on top of a flat bed truck. The box has a mass of m = 20 kg. The coefficient of static friction between the
box and truck is u, = 0.81 and the coefficient of kinetic friction between the box and truck is Hk = 0.62.
1) The truck accelerates from rest to v; = 16 m/s in t = 12 s (which is slow enough that the box will not slide). What is
the acceleration of the box?
m/s Submit
You currently have O submissions for this question. Only 5 submission are allowed.
You can make 5 more submissions for this question.
2) In the previous situation, what is the frictional force the truck exerts on the box?
N Submit
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3) What is the maximum acceleration the truck can have before the box begins to slide?
m/s Submit
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4) Now the acceleration of the truck remains at that value, and the box begins to slide. What is the acceleration of the
box?
m/s Submit
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5) With the box still on the truck, the truck attains its maximum velocity. As the truck comes to a stop at the next stop
light, what is the magnitude of the maximum deceleration the truck can have without the box sliding?
m/s Submit
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Transcribed Image Text:A box rests on top of a flat bed truck. The box has a mass of m = 20 kg. The coefficient of static friction between the box and truck is u, = 0.81 and the coefficient of kinetic friction between the box and truck is Hk = 0.62. 1) The truck accelerates from rest to v; = 16 m/s in t = 12 s (which is slow enough that the box will not slide). What is the acceleration of the box? m/s Submit You currently have O submissions for this question. Only 5 submission are allowed. You can make 5 more submissions for this question. 2) In the previous situation, what is the frictional force the truck exerts on the box? N Submit You currently have 0 submissions for this question. Only 5 submission are allowed. You can make 5 more submissions for this question. 3) What is the maximum acceleration the truck can have before the box begins to slide? m/s Submit You currently have O submissions for this question. Only 5 submission are allowed. You can make 5 more submissions for this question. 4) Now the acceleration of the truck remains at that value, and the box begins to slide. What is the acceleration of the box? m/s Submit You currently have O submissions for this question. Only 5 submission are allowed. You can make 5 more submissions for this question. 5) With the box still on the truck, the truck attains its maximum velocity. As the truck comes to a stop at the next stop light, what is the magnitude of the maximum deceleration the truck can have without the box sliding? m/s Submit You currently have O submissions for this question. Only 5 submission are allowed. You can make 5 more submissions for this question.
Expert Solution
Step 1

The acceleration of an object is defined as the time rate of change of its velocity, i.e.
a=v-ut
where v is final velocity and u is the initial velocity.

The frictional force is a contact force that opposes the relative motion between two objects in contact.

The two types of friction are static friction and kinetic friction. Static friction is the one that acts when the frictional force is greater than the applied force. It is given as: fs=μsN

and kinetic friction is the one when the friction force is less than the applied force and the object moves relative to the surface in contact and is given as: fk=μkN

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