A drag chute must be designed to reduce the speed of a 1171 kg dragster from 342 km/hr to 80 km/hr in 4seconds. Assume that the drag force is proportional to the velocity (kv).a) What value of the drag coefficient k is needed to accomplish this?kg · s?(Leave an exact answer.)m2k =b) How far (in meters) will the dragster travel in the 4-sec interval?d =meters. (Round to the nearest meter)Question Help: O Message instructorSubmit Question

Solution:-Given thatm=1171 kgwhen t=0; V1=342 km/hrwhen t=4 s; V2=80 km/hrFdrag=kv

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