PROBLEM 7:5 Find the shear stresses in the spar webs and skin of the section shown in the figure given. Shear = 15,000 lb. Torsion about front spar = 600,000 in. lb. Q of rear spar flange I of total section = 300 in = 3 in3 40 r.040 .072 15 A= 520 IN? 10 .040 .045

PROBLEM 7:5 Find the shear stresses in the spar webs and skin of the section shown in the figure given. Shear = 15,000 lb. Torsion about front spar = 600,000 in. lb. Q of rear spar flange I of total section = 300 in = 3 in3 40 r.040 .072 15 A= 520 IN? 10 .040 .045

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

2008 Mechanics of MaterialsX attempt.php A cantilever beam of length L1= 250 mm, L2= 250 mm, and L3= 300 mm supports two toads of P1 = 5 kN and P2 = 6 kN, shown in figure. Determine the shear stress at point B on the web of the cantilevered strut at section a-a. 1=1.78625x10°mm 70 mm Y36.25 mm 20 mm 50 mm LOtfen biriei secin. a808 MPa b. 7.16 MA 8.90 M No
Q8(): For the truss shown in the Figure, if the diameter of pins at A and G are 3 in and 2 in, respectively. Both stresses in A and 70 kips 50 kips 4 ft B 4 ft are double shear. Determine the shear stresses in pins at A and G and the stresses in 9 ft members AG; AF member GF if their diameter is 4 and in.
Given: A steel girder with tallow = 400psi is bolted together as shown has shear, V = 5ksi on the cross-section. Wf flange thickness, tr= 1.5in flange width Wf = 10in web thickness, tw = lin web height, hw = 12in I = 1516.5 in“ Wf Determine: Using exact equations for shear stress and flow, determine the spacing of the top bolts, s, if each bolt can resist F = 550lb
Vertical load is applied to point B of a 10 mm radius cylindrical bar as shown in the figure. Calculate the shear stress occurring in the point.
A W18x71 A36 steel beam is loaded as shown on the figure. Neglect the weight of the beam. Determine the maximum shearing stress of the beam.
A beam carries a uniform distributed load of intensity w in N/m. It was determined that Vmax = 7.5w N, (+)Mmax = 5.2w N-m, (-)Mmax = 4.5w N-m. From the given cross section shown, ytop = 64.183 mm, ybot = 135.817 mm, and INA = 25.059 x 10 6 mm4. The allowable stresses are as follows: σfT = 30 MPa, σfC = 60 MPa, and τ = 10 MPa. a. The safe uniform load considering tensile flexural strees is _____N/m b. The safe uniform load considering compressive flexural stress is _____ N/m. c. The moment inertia of the area about the neutral axis is _____ mm^3. d. The safe uniform load considering maximum shear force is _____ N/m e. Based on your analysis, the safe uniform load to recommend is _____ N/m.
A simply supported beam is subjected to a distributed load of wi=640 N/m and a point load pi = 940 N. Calculate the internal loadings on the cross section at C. %3D D 1. 3. 6. The internal normal load at C is N = 1280 X N. The internal shear load at C is V = 242 XN. The internal bending moment at C is M = 476 o N-m.
2 kip/ft 6 in 10 in B. 40 kip 16 in D. 16 In 5 ft 5 ft 10 ft The simply-supported beam-column above is subjected to a uniformly distributed load and an axial load, as shown. Assume that the Internal resultants on the cross-section passing through point D are as follows: • ND -40 kip • VD 0 Mp = +100 kip-ft Which of the following is closest to the longitudinal normal stress at point D? O-78.1 psi +235 psi O-153 psi O-1.77 ksi H:
Draw shear force and bending moment diagrams. Indicate sign and peak values of internal forces. Use method of sections showing cuts and equations
A steel I-beam has the dimensions shown in the figure and is subjected to a shear force V=80 kN. Determine the shear stress at point P, t=VQ/It (MPa). Also, convert the answer from MPa to psi. Recall, 1 MPa = 145.04 psi. 20 mm 100 mm A 20 mm 15 mm 100 mm P 20 mm N.A. V=80 kN N 300 mm 20mm P 20mm 100mm 15mm 300mm
For the beam loaded as shown, find the maximum allowable value of P if the working stresses are 48 MPa in tension, 140 MPa in compression and 30 MPa in shear.