Problem-4 A liquid (S.G. = 0.9) flows downward through a vertical pipe as shown. Determine a) the pressure drop, Ap= p1-p2 and b) the volume flowrate (Q). Given: h = 100 mm. Assume steady, incompressible, frictionless flow. (S.G.)Mercury = 13.6 300 mm Section – 1 0.6 m Section – 2
Problem-4 A liquid (S.G. = 0.9) flows downward through a vertical pipe as shown. Determine a) the pressure drop, Ap= p1-p2 and b) the volume flowrate (Q). Given: h = 100 mm. Assume steady, incompressible, frictionless flow. (S.G.)Mercury = 13.6 300 mm Section – 1 0.6 m Section – 2
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:**Problem-4**
A liquid (Specific Gravity, S.G. = 0.9) flows downward through a vertical pipe as shown. Determine:
a) the pressure drop, Δp = p₁ - p₂
b) the volume flowrate (Q).
**Given:**
- h = 100 mm.
- Assume steady, incompressible, frictionless flow.
- (S.G.) Mercury = 13.6
**Diagram Explanation:**
- The diagram shows a vertical pipe with two sections: Section-1 and Section-2.
- Section-1 is at the top, where the liquid begins to flow downward.
- Section-2 is at the bottom, where the pipe expands, possibly affecting the flow characteristics.
- The vertical distance between the two sections is 0.6 meters.
- At the lower part of the diagram, there is a manometer containing mercury, used to measure the pressure difference between the two sections.
- The height difference in the mercury column is denoted as 'h' (100 mm) and is used to determine the pressure difference.
- Dimensions of the pipe sections are indicated: the width of Section-1 is 300 mm, while the width at Section-2 is 100 mm.
This setup can be used to calculate the pressure loss due to gravitational and flow effects using manometer principles.
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