Problem 3.78 - Enhanced - with Feedback Aluminum hydroxide reacts with sulfuric acid as follows: 2A1(OH):(s) + 3H,SO, (aq) »Aa (SO,)a(aq) + 6H,O(1) Part A Which reagent is the limiting reactant when 0.700 mol Al(OH); and 0.700 mol H,SO, are allowed to react? H2O(1) O Al(OH), (s) H,SO, (aq) Al, (SO,)a (aq) Previous Answers v Correct Sulfuric acid is the limiting reactant, and aluminum hydrocide is the excess reactant. Therefore. all calculations that determine yield, including stoichiometric conversions, will be based on the initial amount of aluminum hydroocide. Part B How many moles of Al (SO,), can form under these conditions? Express the amount in moles to three significant digits. ΑΣΦ ? n- 0.500 mol Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining • Part C How many moles of the excess reactant remain after the completion of the reaction? Express the amount in moles to three significant digits. ΑΣΦ Imol

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Aluminum hydroxide reacts with sulfuric acid as follows:

2Al(OH)3(s)+3H2SO4(aq)=Al2(SO4)3(aq)+6H2O(l)

1. How many moles of  Al2(SO4)3 can form under these conditions?      Express the amount in moles to three significant digits.

2. How many moles of the excess reactant remain after the completion of the reaction? Express the amount in moles to three significant digits.

Problem 3.78 - Enhanced - with Feedback
Aluminum hydroxide reacts with sulfuric acid as follows:
2A1(OH)2 (s) + 3H,SO,(aq) >Al, (SO,)a (aq) + 6H,O(1)
Part A
Which reagent is the limiting reactant when 0.700 mol Al(OH)3 and 0.700 mol H,SO, are allowed to react?
O H2O(1)
O Al(OH), (s)
• H,SO, (aq)
O AL (SO, )a (aq)
Submit
Previous Answers
Соrect
Sulfuric acid is the limiting reactant, and aluminum hydroxide is the excess reactant. Therefore, all calculations that determine yield, including stoichiometric conversions, will be based on the initial amount of aluminum hydroxide.
Part B
How many moles of Al (SO,)3 can form under these conditions?
Express the amount in moles to three significant digits.
[ΑΣφ
?
n= 0.500
Imol
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 5 attempts remaining
Part C
How many moles of the excess reactant remain after the completion of the reaction?
Express the amount in moles
three significant digits.
ΑΣφ
Imol
Transcribed Image Text:Problem 3.78 - Enhanced - with Feedback Aluminum hydroxide reacts with sulfuric acid as follows: 2A1(OH)2 (s) + 3H,SO,(aq) >Al, (SO,)a (aq) + 6H,O(1) Part A Which reagent is the limiting reactant when 0.700 mol Al(OH)3 and 0.700 mol H,SO, are allowed to react? O H2O(1) O Al(OH), (s) • H,SO, (aq) O AL (SO, )a (aq) Submit Previous Answers Соrect Sulfuric acid is the limiting reactant, and aluminum hydroxide is the excess reactant. Therefore, all calculations that determine yield, including stoichiometric conversions, will be based on the initial amount of aluminum hydroxide. Part B How many moles of Al (SO,)3 can form under these conditions? Express the amount in moles to three significant digits. [ΑΣφ ? n= 0.500 Imol Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part C How many moles of the excess reactant remain after the completion of the reaction? Express the amount in moles three significant digits. ΑΣφ Imol
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