Problem 3. Suppose you have the following probability models appropriate for two experiments,say experiment A and experiment B:outcome probabilitya0.25outcome probability0.100.20.30Y0.3d0.050.5e0.15f0.15Call the probability model on the left the probability model for experiment A and the one on theright the probability model for experiment B. Protblem 7a) Give a probability model appropriate for the "compound" or "joint" experiment which consistsof doing BOTH experiments A and B, independently of each other.b) Give the event (explicitly as a subset of the sample space) in this probability model (for thejoint experiment) which corresponds to getting outcome "a" in Experiment A. What is itsprobability, and why?c) Describe a possible "Experiment A" and "Experiment B". That is, describe experiments forwhich the probability models given above are suitable. Then explain what the "joint experi-ment" is in these terms and why the probability model you've given for it is suitable.d) A student named Dougbert gave a probability model in which the event "got 'a' on ExperimentA and 'X' on Experiment B" had probability 0.1. Is Dougbert's model a reasonable model forthe joint experiment? Explain.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question 1 Please use simple probability rules
Problem #4: EXAMPLE 4.15 The lifetime risk of developing pancreatic cancer is about one in 78 (1.28%). Suppose we randomly sample 200 people. Let X = the number of people who will develop pancreatic cancer. a. What is the probability distribution for X? b. Using the formulas, calculate the () mean and (i) standard deviation of X. c. Use your calculator to find the probability that at most eight people develop pancreatic cancer d. Is it more likely that five or six people will develop pancreatic cancer? Justify your answer numerically.
Question 8 An accounting office has 6 incoming telephone lines. The probability distribution of the number of busy lines, X, is as follows: Xi 0 P(X = x₂) 0 |X=2 P(X=6) P(X=4)=0.18 |X=2 P(X=6) P(X=4)=0.18 1 |X=2 P(X=6) P(X-4)=0.18 0.14 2 0.19 3 0.38 4 0.18 1. Use the random variable notation to express symbolically each of the following: An event in which the number of busy lines is exactly 2. 5 0.1 2. Use the above probability distribution table to find the following: a. P(0 1) 6 0.01 The probability of an event in which the number of busy lines is exactly 6. The probability of an event in which the number of busy lines is exactly 4 is equal to 0.18. (Round the answer to 2 decimals) (Round the answer to 2 decimals) (Round the answer to 2 decimals) Total 1
QUESTION 15 Suppose that in a given town, 60% of the population is under age 40 (event A). It is found that the proportion of residents under age 40 who support mandatory inoculation is 0.72. The proportion of residents over age 40 who support mandatory inoculation is 0.52. Let event B = support mandatory inoculation. Define the term probability by choosing the correct answer below. Probability is the long-run event. Probability is the frequency of an event. Probability is the fraction of times an event occurs in n independent replications of an experiment. Probability is the long-run relative frequency of an event.
Question 14 of 14, Step 1 of 2 Suppose that you and a friend are playing cards and you decide to make a friendly wager. The bet is that you will draw two cards without replacement from a standard deck if both cards are diamonds, your friend will pay you $810. Otherwise, you have to pay your friend $49. Step 1 of 2: What is the expected value of your bet? Round your answer to two decimal places. Losses must be expressed as negative values. Answer winnens in new window) Tables Keypad Keyboard Shortcuts
Question 8 W Data was collected from a simple random sample of 200 cell phone users age 18 or older in the United States. Each user was categorized by age-group and by whether he or she uses a certain cell phone app. The table shown summarizes the data, with expected cell counts in parentheses. Uses Cell Phone App Yes No Total Young Adults 4 (15.2) 76 (64.8) 80 Older Adults 29 (19.38) 73 (82.62) 102 Age-Group Elderly Adults 5 (3.42) 13 (14.58) 18 Total 38 162 200 Which statement is true about whether the conditions for a chi-square test for independence have been met? A All necessary conditions are satisfied to apply a chi-square test for independence between age-group and texting use by cell phone users. В The data from the different age-groups are not the result of independent random samples; therefore, the conditions for the test are not met. The total sample size in one or more of the age-groups is too small to meet the conditions of the chi-square test for independence. Not all of…
Can you help with question D.
QUESTION 4 The current price of a stock is $50. Suppose the following distribution describes the possible prices that the stock will be in 1 year: the probability the stock price will be 44 is 0, the probability the stock price will be 0.09 is 0.15, the probability the stock price will be 60 is 0.36, otherwise the stock price will be 69. What is the expected value of the stock price in 1 year? (please express your answer using 2 decimal places)
Question 1-28 The probability that Juliana will take a particular type of dance class is shown in the chart below. She will definitely take either ballet or jazz, but not both. The probability that she will take jazz on Wednesday night is 27%. If the probability that she will take Ballet is 70%, what is the probability that she will take jazz on Saturday morning? Tuesday Night Ballet Thursday Night Dance Class Saturday morning Jazz Wednesday Night 3% 10% O 27% o o o
Question 9 The following table provides a probability distribution for the random variable x. f(x) 0.2 4 0.3 6. 0.5 What is the expected value of E(x)? Keep one decimal places of your answer. A Moving to another question will save this response.
QUESTION 5 The following table provides a probability distribution for the random variable y. y f(y) 2 0.30 4 0.10 7 0.20 8 0.40 (a) Compute E(y). E(y) = (b) Compute Var(y) and σ. (Round your answer for σ to two decimal places.) Var(y) =σ=

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