Let X be a continuous random variable representing the (exact) lifetime of your TV set, measured in years. A simple model for X is that is an Exponential (A) random variable. You may assume that your brand of TV has an average lifetime of 20 years. 2 (a) What is the probability that the TV fails in the first year? (b) What is the probability that it lasts more than 5 years? (c) Consider the event B = {X ≥ 10} that your TV has already lasted 10 years. What is the conditional PDF fx|B(x)? (d) Let Y = X-10. What is the conditional probability of Y given B = {X ≥ 10}? You can get this by simply transforming fx|³(x) as fy|B(y) = fx|B(y +10). (e) Assume your TV has already lasted 10 years. What is the probability that it fails during the next year?
Let X be a continuous random variable representing the (exact) lifetime of your TV set, measured in years. A simple model for X is that is an Exponential (A) random variable. You may assume that your brand of TV has an average lifetime of 20 years. 2 (a) What is the probability that the TV fails in the first year? (b) What is the probability that it lasts more than 5 years? (c) Consider the event B = {X ≥ 10} that your TV has already lasted 10 years. What is the conditional PDF fx|B(x)? (d) Let Y = X-10. What is the conditional probability of Y given B = {X ≥ 10}? You can get this by simply transforming fx|³(x) as fy|B(y) = fx|B(y +10). (e) Assume your TV has already lasted 10 years. What is the probability that it fails during the next year?
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![Problem 4.5 (Video 3.3, 3.4)
Let X be a continuous random variable representing the (exact) lifetime of your TV set, measured
in years. A simple model for X is that is an Exponential (A) random variable. You may assume
that your brand of TV has an average lifetime of 20 years.
2
(a) What is the probability that the TV fails in the first year?
(b) What is the probability that it lasts more than 5 years?
(c) Consider the event B = {X ≥ 10} that your TV has already lasted 10 years. What is the
conditional PDF ƒx\B(x)?
(d) Let Y = X - 10. What is the conditional probability of Y given B = {X ≥ 10}? You can
get this by simply transforming ƒx|ß(x) as fy|B(y) = fx|b(y +10).
(e) Assume your TV has already lasted 10 years. What is the probability that it fails during
the next year?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F02681530-b6ca-4d72-bfd1-7260256101ab%2F9f2cfad1-27b7-492a-9560-368b759de53e%2Fszoaw2_processed.png&w=3840&q=75)
Transcribed Image Text:Problem 4.5 (Video 3.3, 3.4)
Let X be a continuous random variable representing the (exact) lifetime of your TV set, measured
in years. A simple model for X is that is an Exponential (A) random variable. You may assume
that your brand of TV has an average lifetime of 20 years.
2
(a) What is the probability that the TV fails in the first year?
(b) What is the probability that it lasts more than 5 years?
(c) Consider the event B = {X ≥ 10} that your TV has already lasted 10 years. What is the
conditional PDF ƒx\B(x)?
(d) Let Y = X - 10. What is the conditional probability of Y given B = {X ≥ 10}? You can
get this by simply transforming ƒx|ß(x) as fy|B(y) = fx|b(y +10).
(e) Assume your TV has already lasted 10 years. What is the probability that it fails during
the next year?
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VIEWStep 4: Determine the conditional PDF ƒx\B(x), where B = {X ≥ 10}
VIEWStep 5: Determine the conditional probability of Y given B = {X ≥ 10} if Y = X - 10
VIEWStep 6: Determine the probability that it fails during the next year, if TV has already lasted 10 years
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