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Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1– p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. 0.01 ре (1- р)е " (1– p)eº4 -20 (A) ре 100 10,000 100 10,000 (1– p)e 0.01 (B) pe pe0 (1– p)e® 100 10,000 100 10,000 ре, (1- р)е 0.01 -20 (1– p)e02 pe 100 (C) 100 10,000 10,000 pe. (1– p)e 001 pe 20. (1- p)e02 (D) 100 10,000 100 10,000 el 0.01 e + 100 02 (E) +(1- p)| p. 10.000 100 10.000

Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1– p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. 0.01 ре (1- р)е " (1– p)eº4 -20 (A) ре 100 10,000 100 10,000 (1– p)e 0.01 (B) pe pe0 (1– p)e® 100 10,000 100 10,000 ре, (1- р)е 0.01 -20 (1– p)e02 pe 100 (C) 100 10,000 10,000 pe. (1– p)e 001 pe 20. (1- p)e02 (D) 100 10,000 100 10,000 el 0.01 e + 100 02 (E) +(1- p)| p. 10.000 100 10.000

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1– p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. -0.01 pe (1– p)e“ pe 20 (1– p)e0² -0.2 (A) 100 10,000 100 10,000 pe (1– p)e“ -0.01 (B) pe (1– p)e02' 100 10,000 100 10,000 pe, (1- p)e0. 20 (1– p)eº -0.01 pe 100 -0.2 (C) pe 10,000 100 10,000 pe, (1- p)e 00i -0.01 (D) -20 ре (1– p)e02 100 10,000 100 10,000 e 0.01 +(1– p) e -20 (E) р. 100 10,000 100 10,000
Transcribed Image Text:Losses come from a mixture of an exponential distribution with mean 100 with probability p and an exponential distribution with mean 10,000 with probability 1– p. Losses of 100 and 2000 are observed. Determine the likelihood function of p. -0.01 pe (1– p)e“ pe 20 (1– p)e0² -0.2 (A) 100 10,000 100 10,000 pe (1– p)e“ -0.01 (B) pe (1– p)e02' 100 10,000 100 10,000 pe, (1- p)e0. 20 (1– p)eº -0.01 pe 100 -0.2 (C) pe 10,000 100 10,000 pe, (1- p)e 00i -0.01 (D) -20 ре (1– p)e02 100 10,000 100 10,000 e 0.01 +(1– p) e -20 (E) р. 100 10,000 100 10,000
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