An accounting office has 6 incoming telephone lines. The probability distribution of the number of busy lines, X, is as follows: Ti P(X = x₁)| 0 0 X=2 P(X=6) P(X=4)=0.18 X=2 P(X=6) P(X=4)=0.18 1 X=2 P(X=6) P(X-4)=0.18 0.14 2 0.19 3 0.38 4 1. Use the random variable notation to express symbolically each of the following: An event in which the number of busy lines is exactly 2. 0.18 5 0.1 2. Use the above probability distribution table to find the following: a. P(0 < X < 2) = b. P(X<2) c. P(X > 1) = 6 0.01 The probability of an event in which the number of busy lines is exactly 6. The probability of an event in which the number of busy lines is exactly 4 is equal to 0.18. (Round the answer to 2 decimals) (Round the answer to 2 decimals) (Round the answer to 2 decimals) Total 1

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Question 8
An accounting office has 6 incoming telephone lines. The probability distribution of the number of busy
lines, X, is as follows:
Xi
0
P(X = x₂) 0
|X=2
P(X=6)
P(X=4)=0.18
|X=2
P(X=6)
P(X=4)=0.18
1
|X=2
P(X=6)
P(X-4)=0.18
0.14
2
0.19
3
0.38
4
0.18
1. Use the random variable notation to express symbolically each of the following:
An event in which the number of busy lines is exactly 2.
5
0.1
2. Use the above probability distribution table to find the following:
a. P(0 < X < 2)
b. P(X < 2)
c. P(X > 1)
6
0.01
The probability of an event in which the number of busy lines is exactly
6.
The probability of an event in which the number of busy lines is exactly 4
is equal to 0.18.
(Round the answer to 2 decimals)
(Round the answer to 2 decimals)
(Round the answer to 2 decimals)
Total
1
Transcribed Image Text:Question 8 An accounting office has 6 incoming telephone lines. The probability distribution of the number of busy lines, X, is as follows: Xi 0 P(X = x₂) 0 |X=2 P(X=6) P(X=4)=0.18 |X=2 P(X=6) P(X=4)=0.18 1 |X=2 P(X=6) P(X-4)=0.18 0.14 2 0.19 3 0.38 4 0.18 1. Use the random variable notation to express symbolically each of the following: An event in which the number of busy lines is exactly 2. 5 0.1 2. Use the above probability distribution table to find the following: a. P(0 < X < 2) b. P(X < 2) c. P(X > 1) 6 0.01 The probability of an event in which the number of busy lines is exactly 6. The probability of an event in which the number of busy lines is exactly 4 is equal to 0.18. (Round the answer to 2 decimals) (Round the answer to 2 decimals) (Round the answer to 2 decimals) Total 1
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