A contractor is required by a county planning department to submit one, two, three, four, five, six, or seven forms (depending on the nature of the project) in applying for a building permit. Let Y = the number of forms required of the next applicant. The probability that y forms are required is known to be proportional to y-that is, p(y) = ky for y = 1,..., 7. (Enter your answers as fractions.) (a) What is the value of k? [Hint: k = 1/28 (b) What is the probability that at most five forms are required? X p(y) = 1] y = 1 Ź (c) What is the probability that between four and six forms (inclusive) are required? X (d) Could p(y) = y² for y = 1, ..., 7 be the pmf of Y? 145 ---Select-- , because Ź y = 1 p(y) =
A contractor is required by a county planning department to submit one, two, three, four, five, six, or seven forms (depending on the nature of the project) in applying for a building permit. Let Y = the number of forms required of the next applicant. The probability that y forms are required is known to be proportional to y-that is, p(y) = ky for y = 1,..., 7. (Enter your answers as fractions.) (a) What is the value of k? [Hint: k = 1/28 (b) What is the probability that at most five forms are required? X p(y) = 1] y = 1 Ź (c) What is the probability that between four and six forms (inclusive) are required? X (d) Could p(y) = y² for y = 1, ..., 7 be the pmf of Y? 145 ---Select-- , because Ź y = 1 p(y) =
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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
Transcribed Image Text:**Educational Content: Probability and Statistics**
A contractor is required by a county planning department to submit *one, two, three, four, five, six, or seven* forms (depending on the nature of the project) in applying for a building permit. Let \(Y\) represent the number of forms required for the next applicant. The probability that \(y\) forms are required is known to be proportional to \(y\)—that is, \(p(y) = ky\) for \(y = 1, \ldots, 7\).
The following problems explore how to calculate probabilities and determine whether a given function is a valid probability mass function (pmf).
**(a) What is the value of \(k\)?**
- \(\sum_{y=1}^{7} p(y) = 1\)
- Given \(p(y) = ky\), find \(k\).
- Solved: \(k = \frac{1}{28}\) ✔
**(b) What is the probability that at most five forms are required?**
- To solve, compute \(P(Y \leq 5)\).
- Status: Incorrect ❌
**(c) What is the probability that between four and six forms (inclusive) are required?**
- Calculate \(P(4 \leq Y \leq 6)\).
- Status: Incorrect ❌
**(d) Could \(p(y) = \frac{y^2}{145}\) for \(y = 1, \ldots, 7\) be the pmf of \(Y\)?**
- Verify if \(\sum_{y=1}^{7} p(y) = 1\).
- Choose: \(\_\_\_\_\_\_\_\), because \(\sum_{y=1}^{7} p(y) = \_\_\_\_\_\_\_\_\).
Remember, a valid pmf must satisfy the condition that the sum of \(p(y)\) over all possible values of \(Y\) equals 1.
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