Problem 24. The thermodynamics of decomposition reactions The thermodynamic data of the species involved in the reactions are listed in the table below: Ag₂CO3(s) Ag₂O(s) CO₂(g) AH (298K) (kJ mol-¹) -501.66 -30.58 -393.51 S (298K) (J mol-¹ K-¹) 167.4 121.8 213.8 m Cpm (J mol-¹ K-¹) 109.6 65.7 37.6 24-1 The decomposition of Ag2CO3 proceeds with the chemical equation: Ag2CO3(s) →Ag2O(s) + CO₂(g). Calculate the standard equilibrium constant, K (298 K), of the reaction at 298 K. 24-2 The enthalpy and entropy changes with temperature are given by the equations: AH (T₂)=AH (T) +AC (T₂-T₂) AS (T₂)=4,S (T₂)+A,C in ¹2 T₁ In order to dry Ag2CO3(s) with a hot air flow under a constant pressure of 105 Pa and a constant temperature of 383 K, calculate the minimum partial pressure of CO2(g) needed in the air flow to avoid the decomposition of Ag2CO3(s).

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Problem 24. The thermodynamics of decomposition reactions
The thermodynamic data of the species involved in the reactions are listed in the table below:
Ag₂CO3(s)
Ag₂O(s)
CO₂(g)
AH (298K) (kJ mol-¹)
-501.66
-30.58
-393.51
S (298K) (J mol-¹ K-¹)
167.4
121.8
213.8
m
C (J mol-¹ K-¹)
109.6
65.7
37.6
24-1 The decomposition of Ag2CO3 proceeds with the chemical equation: Ag2CO3(s) →Ag₂O(s) +
CO₂(g). Calculate the standard equilibrium constant, K (298 K), of the reaction at 298 K.
24-2 The enthalpy and entropy changes with temperature are given by the equations:
A₂H (T₂)=AH (T₂)+A,C# (T₂ −T₂)
AS✯ (T₂)=øSª (T₁)+øCº In
T₂
T₁
In order to dry Ag₂CO3(s) with a hot air flow under a constant pressure of 105 Pa and a constant
temperature of 383 K, calculate the minimum partial pressure of CO₂(g) needed in the air flow to
avoid the decomposition of Ag2CO3(s).
Transcribed Image Text:Problem 24. The thermodynamics of decomposition reactions The thermodynamic data of the species involved in the reactions are listed in the table below: Ag₂CO3(s) Ag₂O(s) CO₂(g) AH (298K) (kJ mol-¹) -501.66 -30.58 -393.51 S (298K) (J mol-¹ K-¹) 167.4 121.8 213.8 m C (J mol-¹ K-¹) 109.6 65.7 37.6 24-1 The decomposition of Ag2CO3 proceeds with the chemical equation: Ag2CO3(s) →Ag₂O(s) + CO₂(g). Calculate the standard equilibrium constant, K (298 K), of the reaction at 298 K. 24-2 The enthalpy and entropy changes with temperature are given by the equations: A₂H (T₂)=AH (T₂)+A,C# (T₂ −T₂) AS✯ (T₂)=øSª (T₁)+øCº In T₂ T₁ In order to dry Ag₂CO3(s) with a hot air flow under a constant pressure of 105 Pa and a constant temperature of 383 K, calculate the minimum partial pressure of CO₂(g) needed in the air flow to avoid the decomposition of Ag2CO3(s).
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