= Problem 2.15 In the ground state of the harmonic oscillator, what is the probability (correct to three significant digits) of finding the particle outside the classically allowed region? Hint: Classically, the energy of an oscillator is E = (1/2)ka² = (1/2)mw²a², where a is the amplitude. So the "classically allowed region" for an oscillator of energy E extends from -√2E/mw² to +√2E/mw². Look in a math table under "Normal Distribution" or "Error Function" for the numerical value of the integral.

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Problem 2.15 In the ground state of the harmonic oscillator, what is the probability
(correct to three significant digits) of finding the particle outside the classically
allowed region? Hint: Classically, the energy of an oscillator is E = (1/2)ka² =
(1/2)mw²a², where a is the amplitude. So the "classically allowed region" for an
oscillator of energy E extends from -√2E/mw² to +√2E/mw². Look in a math
table under "Normal Distribution" or "Error Function" for the numerical value of
the integral.
Transcribed Image Text:Problem 2.15 In the ground state of the harmonic oscillator, what is the probability (correct to three significant digits) of finding the particle outside the classically allowed region? Hint: Classically, the energy of an oscillator is E = (1/2)ka² = (1/2)mw²a², where a is the amplitude. So the "classically allowed region" for an oscillator of energy E extends from -√2E/mw² to +√2E/mw². Look in a math table under "Normal Distribution" or "Error Function" for the numerical value of the integral.
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