Problem 2Consider the Gaussian surface shown in Figure 2. A uniformexternal electric field E, having magnitude 3.20 x 103 N/Cand parallel to the xz plane with an angle of 36.87° measuredfrom the +x axis toward the +z axis, enters through face 1(back face). In addition, a uniform electric field E, ofmagnitude 6.40 x 103 N/C traveling in the same direction asE, , flows outwardly through face 2 (front face).0,45 m0,30 mEn0.50 mFigure 2. Gaussian surface in the form of a prism throughwhich two fields pass. Determine:The net charge contained within the surface.Note: the following table contains the unit normal vectors toeach face.FaceUnit vectorî = -0,8 î – 0,6 kî2 = 0,8 î + 0,6 kîz = -0,6 î + 0,8 kîî4 = 0,6 î – 0,8 kîîg = 1 jîîo = -1j1 back2 front3 left4 right5 top6 bottomHint: calculate the components of the electric fields.

Let us first write the electric fields in the vector form:…

Problem 2 Consider the Gaussian surface shown in Figure 2. A uniform external electric field E, having magnitude 3.20 x 103 N/C and parallel to the xz plane with an angle of 36.87° measured from the +x axis toward the +z axis, enters through face 1 (back face). In addition, a uniform electric field E, of magnitude 6.40 x 10° N/C traveling in the same direction as E , flows outwardly through face 2 (front face). 0,45 m 0,30 m 0.50 m E, Figure 2. Gaussian surface in the form of a prism through which two fields pass.

Problem 2 Consider the Gaussian surface shown in Figure 2. A uniform external electric field E, having magnitude 3.20 x 103 N/C and parallel to the xz plane with an angle of 36.87° measured from the +x axis toward the +z axis, enters through face 1 (back face). In addition, a uniform electric field E, of magnitude 6.40 x 10° N/C traveling in the same direction as E , flows outwardly through face 2 (front face). 0,45 m 0,30 m 0.50 m E, Figure 2. Gaussian surface in the form of a prism through which two fields pass.