Part CWhat is the electric flux through the cube face S3?Express your answer in newton times meters squared per coulomb.?N- m? /CPart DWhat is the electric flux through the cube face S4?Express your answer in newton times meters squared per coulomb.Vo AEO?N. m? /C The cube in (Figure 1) has sides of length L = 10.0 cm.The electric field is uniform, has a magnitudeE = 4.00 x 10³ N/C, and is parallel to the xy-plane at anangle of 36.9° measured from the +x – axis toward the+y - axis.Part AWhat is the electric flux through the cube face S,?Express your answer in newton times meters squared per coulomb.?N. m² /CPart BFigure< 1 of 1>What is the electric flux through the cube face S,?Express your answer in newton times meters squared per coulomb.S, (top)S6 (back)S3 (right side)(left side)LN. m? /C2 =LS4 (bottom)S, (front)Part C

This is solved by using Gauss's Law

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What is the electric flux through the cube face S2? Express your answer in newton times meters squared per coulomb. S2 (top) S6 (back) ΑΣΦ ? -S3 (right side) (left side) L 2 = N. m2/C y L. S4 (bottom) S5 (front)