part 1 of 2 A uniformly charged conducting plate with area A has a total charge Q which is positive. The figure below shows a cross-sectional view of the plane and the electric field lines due to the charge on the plane. The figure is not drawn to scale. +Q E =( P E Find the magnitude of the field at point P, which is a distance a from the plate. Assume that a is very small when compared to the dimensions of the plate, such that edge effects can be ignored. part 2 of 2 Two uniformly charged conducting plates are parallel to each other. They each have area A. Plate #1 has a positive charge Q while plate #2 has a charge -3 Q. +Q -3Q 1.1² X #1 #2 Using the superposition principle find the magnitude of the electric field at a point P in the gap. ○ 1. || Ep|| = €0 Q a² 2. ||EP|| = 2 €0 QA A ● 3. ||EP|| = 4. ||ĒP|| Q Απέρα 5. ||EP|| = 4 π €₁a Q ● 6. ||ĒP|| = 4 π € a ² Q Q ● 7. ||EP|| = 47% G² = Q ● 8. ||EP|| = 28 A 9. ||EP|| = €0 QA ○ 1. ||ĒP|| = = 3 Q 2. ||EP|| = 260 A 4. ||EP|| Q €0 3. ||EP|| = 0 = 4 Q €0 A 5. ||EP|| = 24 Q A Q ○ 6. ||EP|| = 28 A ||Ēp|| 8. ||ĒP|| = ● 7. ||EP|| = 32 3Q A A Q ○ 9. ||ĒP|| = 38 A ○ 10. ||EP|| = 59 5Q A
part 1 of 2 A uniformly charged conducting plate with area A has a total charge Q which is positive. The figure below shows a cross-sectional view of the plane and the electric field lines due to the charge on the plane. The figure is not drawn to scale. +Q E =( P E Find the magnitude of the field at point P, which is a distance a from the plate. Assume that a is very small when compared to the dimensions of the plate, such that edge effects can be ignored. part 2 of 2 Two uniformly charged conducting plates are parallel to each other. They each have area A. Plate #1 has a positive charge Q while plate #2 has a charge -3 Q. +Q -3Q 1.1² X #1 #2 Using the superposition principle find the magnitude of the electric field at a point P in the gap. ○ 1. || Ep|| = €0 Q a² 2. ||EP|| = 2 €0 QA A ● 3. ||EP|| = 4. ||ĒP|| Q Απέρα 5. ||EP|| = 4 π €₁a Q ● 6. ||ĒP|| = 4 π € a ² Q Q ● 7. ||EP|| = 47% G² = Q ● 8. ||EP|| = 28 A 9. ||EP|| = €0 QA ○ 1. ||ĒP|| = = 3 Q 2. ||EP|| = 260 A 4. ||EP|| Q €0 3. ||EP|| = 0 = 4 Q €0 A 5. ||EP|| = 24 Q A Q ○ 6. ||EP|| = 28 A ||Ēp|| 8. ||ĒP|| = ● 7. ||EP|| = 32 3Q A A Q ○ 9. ||ĒP|| = 38 A ○ 10. ||EP|| = 59 5Q A
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Transcribed Image Text:part 1 of 2
A uniformly charged conducting plate with
area A has a total charge Q which is positive.
The figure below shows a cross-sectional view
of the plane and the electric field lines due to
the charge on the plane. The figure is not
drawn to scale.
+Q
E
E
Find the magnitude of the field at point P,
which is a distance a from the plate. Assume
that a is very small when compared to the
dimensions of the plate, such that edge effects
can be ignored.
part 2 of 2
Two uniformly charged conducting plates
are parallel to each other. They each have
area A. Plate #1 has a positive charge Q
while plate #2 has a charge -3Q.
-3Q
11
#1
x
#2
Using the superposition principle find the
magnitude of the electric field at a point P in
the gap.
1. ||Ēp|| = €0 Q a²
● 2. ||EP|| = 2 €0 Q A
● 3. ||EP|| =
4. ||Ēp||
Q
4 π Eo a
● 5. ||EP|| = 4 π € а Q
6. ||Ēp|| = 4 π €0 a² Q
●
Q
● 7. ||EP|| = 470 0²
●
Q
● 8. ||EP|| = 26 A
||Ēp||
=
A
1. ||Ép||
€0
9. ||Ēp|| = €0 Q A
●
=
3 Q
○ 2. ||EP|| = 260 A
€0
8. ||Ēp||
3. ||EP|| = 0
4. || Ep|| = 44/1
||Ēp||
Q
A
● 5. ||EP|| = 22
Q
A
● 6. ||ĒP|| = 28 A
А
3Q
● 7. ||EP|| = 34
A
= A
€
Q
● 9. ||EP|| = 38 A
||Ēp||
Q
● 10. ||EP|| = 52 A
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