PROBLEM 2: As shown in the Figure, a rigid beam with negligible weight is pinned at one end and attached to two vertical rods. The beam was initially horizontal before the load W=35.11 kips was applied. For the steel rod: A = 0.5 in^2, L = 90 in. For the bronze rod: A = 2 in^2, L = 30 in. Determine the following: 1. Force in the steel rod 2. Force in the bronze rod 3. Stress in the steel rod A Bronze E = 12 x 10° psi -3 ft→ 8 ft Steel E = 29 x 106 W psi 4 ft-> lbs lbs psi

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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PROBLEM 2:
As shown in the Figure, a rigid beam with negligible weight is pinned at one end and attached to two
vertical rods. The beam was initially horizontal before the load W=35.11 kips was applied. For the steel
rod: A = 0.5 in^2, L = 90 in. For the bronze rod: A = 2 in^2, L = 30 in. Determine the following:
1. Force in the steel rod
2. Force in the bronze rod
3. Stress in the steel rod
4. Stress in the bronze rod
5. Vertical movement of W, OW
Bronze
E = 12 x 10° psi
E = 29 x 106 psi
1-
3 ft→
8 ft
A
6. Vertical movement at the bronze rod, õbr
7. Vertical movement at the steel rod, öst
8. Vertical reaction at the pinned end (include sign)
9. Shearing stress in the pin at A assuming the
diameter of the pin is 1.5 inches (assume double shear)
W
Steel
4 ft →>>
lbs
lbs
psi
psi
in
in
in
lbs
psi
Transcribed Image Text:PROBLEM 2: As shown in the Figure, a rigid beam with negligible weight is pinned at one end and attached to two vertical rods. The beam was initially horizontal before the load W=35.11 kips was applied. For the steel rod: A = 0.5 in^2, L = 90 in. For the bronze rod: A = 2 in^2, L = 30 in. Determine the following: 1. Force in the steel rod 2. Force in the bronze rod 3. Stress in the steel rod 4. Stress in the bronze rod 5. Vertical movement of W, OW Bronze E = 12 x 10° psi E = 29 x 106 psi 1- 3 ft→ 8 ft A 6. Vertical movement at the bronze rod, õbr 7. Vertical movement at the steel rod, öst 8. Vertical reaction at the pinned end (include sign) 9. Shearing stress in the pin at A assuming the diameter of the pin is 1.5 inches (assume double shear) W Steel 4 ft →>> lbs lbs psi psi in in in lbs psi
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