2.4 The truss shown is the same as in Example 2.1 except that the area of bar ab isa variable. E = 200,000 MPa. (a) For what value of Aah is v. = 0? Is this a function ofthe magnitude of the applied load? (b) Is it possible to obtain zero u, by varying A?(c) Suppose the applied load were vertical rather than horizontal, would it then bepossible to obtain zero u, by varying Aab? If so, for what value of Aab? What wouldbe the corresponding v.?500 kNFah = +400.6 kNAab4 m6 m3 mProblem 2.4Fac = -277.8 kNAae = 8000 mm?

sinϕab = 662 + 42 = 652 , cosϕab = 452sinϕac = 35 , cosϕac = 45 Modulus of Elasticity (E)…

Answered: 24 The truss shown is the same as in…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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2.4 The truss shown is the same as in Example 2.1 except that the area of bar ab is
a variable. E = 200,000 MPa. (a) For what value of Aah is v. = 0? Is this a function of
the magnitude of the applied load? (b) Is it possible to obtain zero u, by varying A?
(c) Suppose the applied load were vertical rather than horizontal, would it then be
possible to obtain zero u, by varying Aab? If so, for what value of Aab? What would
be the corresponding v.?
500 kN
Fah = +400.6 kN
Aab
4 m
6 m
3 m
Problem 2.4
Fac = -277.8 kN
Aae = 8000 mm?

Expert Solution

Step 1 : Diagram

$\sin ϕ_{a b} = \frac{6}{\sqrt{6^{2} + 4^{2}}} = \frac{6}{\sqrt{52}}, \cos ϕ_{a b} = \frac{4}{\sqrt{52}} \sin ϕ_{a c} = \frac{3}{5}, \cos ϕ_{a c} = \frac{4}{5}$

$\begin{array}{rcl} M o d u l u s o f E l a s t i c i t y (E) & = & 200000 M P a \\ v_{a} & = & 0 \end{array}$

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