Problem 1(A)- In reference to the power system shown below, the system is operating at nomina voltage without pre-fault currents (load currents ignored) when a bolted ( = 0 p .u .) single line- to ground fault occurs on phase A at bus 3. Both machines are grounded through reactance. X, = X, =15% X, = 50% 2 3 4 to Y 100MVA,20KV 100MVA 100MVA 100MVA,20KV 20Υ/345Y- kV X, = X, = 20% X, = X, = X, = 8% X,= 20% 20Υ/345Υ - kV X, = X, = 20% X2 = 20% X = X, = X, = 8% X, = 4% X, = 4% X, = 5% X = 5% Fig. 1-Single-line diagram for the system in problems 1-A, 1-B, and 1-C (a) The system's Thevenin equivalent positive-, negative-, and zero-sequence networks (b) The fault current (p.u.) at phase A

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
icon
Related questions
icon
Concept explainers
Question
100%
Problem 1(A)- In reference to the power system shown below, the system is operating at nominal
voltage without pre-fault currents (load currents ignored) when a bolted ( = 0p .u .) single line-
to
ground fault occurs on phase A at bus 3. Both machines are grounded through reactance.
X, = X, =15%
X, = 50%
1
2
3
4
my O
어。
100MVA,20KV
100MVA
100MVA
100MVA,20KV
X, = X = 20%
20Υ/345Y - kV
20Y /345Y – kV
X, = X = 20%
X2 = 20%
X, = X, = X, = 8%
X, = X, = X, = 8%
X2 = 20%
%3D
X, = 4%
X, = 4%
X, = 5%
X = 5%
Fig. 1-Single-line diagram for the system in problems 1-A, 1-B, and 1-C
(a) The system's Thevenin equivalent positive-, negative-, and zero-sequence networks
(b) The fault current (p.u.) at phase A
Transcribed Image Text:Problem 1(A)- In reference to the power system shown below, the system is operating at nominal voltage without pre-fault currents (load currents ignored) when a bolted ( = 0p .u .) single line- to ground fault occurs on phase A at bus 3. Both machines are grounded through reactance. X, = X, =15% X, = 50% 1 2 3 4 my O 어。 100MVA,20KV 100MVA 100MVA 100MVA,20KV X, = X = 20% 20Υ/345Y - kV 20Y /345Y – kV X, = X = 20% X2 = 20% X, = X, = X, = 8% X, = X, = X, = 8% X2 = 20% %3D X, = 4% X, = 4% X, = 5% X = 5% Fig. 1-Single-line diagram for the system in problems 1-A, 1-B, and 1-C (a) The system's Thevenin equivalent positive-, negative-, and zero-sequence networks (b) The fault current (p.u.) at phase A
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Knowledge Booster
Fault analysis
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,