Problem 12IR Spectrum(quid fim)1.40001250300020001600V (cm)10012000.0P80080Mass Spectrum0.5M 156UV spectrum291275.00 mg/10 mtspath length 050 cmsolvent oysiohexane1.0contains a halogen4080120160m/e200240280200250300350Catiz1F13C NMR Spectrum(50.0 MHz CDCI, solution)No TMS inthis sampiesolventproton coupledproton decouplednキし12080408 (ppm)200160H NMR Spectrum(200 MHz. CDCI, solution)3214.8 (p9.810yead aseq jo %

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Problem 12 IR Spectrum (quid fim) 1. 1250 4000 3000 2000 V (cm) 1600 1200 0.0P B00 100 C-Y 80 Mass Spectrum 0.5 M 156 UV spectrum 29 500 mg/10 mts path length 050 cm solvent oyslohexane 127 1.0 contains a halogen 40 80 120 160 200 240 280 200 250 300 350 m/e 2. (nm) Catiz1F 13C NMR Spectrum (500 MHz. CDCI, solution) No TMS in this sampie solvent proton coupled nキし proton decoupled 8 (ppm) 80 40 200 160 120 H NMR Spectrum (200 MHz. CDCI, solution) 2 1 4. 3 8 (PF % of base peak

Problem 12 IR Spectrum (quid fim) 1. 1250 4000 3000 2000 V (cm) 1600 1200 0.0P B00 100 C-Y 80 Mass Spectrum 0.5 M 156 UV spectrum 29 500 mg/10 mts path length 050 cm solvent oyslohexane 127 1.0 contains a halogen 40 80 120 160 200 240 280 200 250 300 350 m/e 2. (nm) Catiz1F 13C NMR Spectrum (500 MHz. CDCI, solution) No TMS in this sampie solvent proton coupled nキし proton decoupled 8 (ppm) 80 40 200 160 120 H NMR Spectrum (200 MHz. CDCI, solution) 2 1 4. 3 8 (PF % of base peak

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

UV Visible Spectroscopy

Spectroscopy refers to the absorption or emission of light or other radiations by matter. When a substance or chemical absorbs light or radiation, they reach an excited state followed by de-excitation or emission of the light or radiation forming distinct spectra. UV-visible spectroscopy or ultraviolet-visible refers to the absorption and emission in the ultraviolet and visible regions of the electromagnetic spectrum.

Question

Problem 12
IR Spectrum
(quid fim)
1.
4000
1250
3000
2000
1600
V (cm)
100
1200
0.0P
800
80
Mass Spectrum
0.5
M 156
UV spectrum
29
127
5.00 mg/10 mts
path length 050 cm
solvent oysiohexane
1.0
contains a halogen
40
80
120
160
m/e
200
240
280
200
250
300
350
Catiz1F
13C NMR Spectrum
(50.0 MHz CDCI, solution)
No TMS in
this sampie
solvent
proton coupled
proton decoupled
nキし
120
80
40
8 (ppm)
200
160
H NMR Spectrum
(200 MHz. CDCI, solution)
3
2
1
4.
8 (p
9.
8
10
yead aseq jo %

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A student performed a series of reactions and obtained the spectral data provided. The reaction sequence is shown below.. What are the structures for A, B, C, and D? Compound B NMR (relative integrated areas below peaks) CH;CH,O°N 1. BHTHF N-bromosuccnimide A CH;CH,OH B 2. H,O,/OH- D hv reflux Compound A NMR (relative integrated areas below peaks) PPM 5 Compound B IR INFRARED SPECTRUM PPM 5 1 6 0.8 Compound A IR INFRARED SPECTRUM 0.6 0.8 0.4 0.4 0.2- 3000 2000 Wavenumber (cm-1) 1000 The MS of compound B shows an M+ peak at 198 and an M+2 peak at 200 with a relative abundance of 1:0.97 2000 Wavenumber (cm-1) 3000 1000 Transmitance Relative Transmittance
Can you please help explain how to approach this unknown spectroscopy problem?
Identify the peaks and structer.
Problem 12 IR Spectrum (quid fim) -- 12 s0 4000 3000 2000 1600 1200 600 0.0P v (cm") 100 Mass Spectrum 0.5 80 M 156 UW spectrum 5.00 mg/10 mis path length 050 cm solvent cyclohexane 127 1.0 29 contains a halogen 1.5 40 80 120 160 200 240 280 200 250 300 350 m/e 2 (nm) 13C NMR Spectrum No TMS in this sample (50.0 MHz CDCI, solution) solvent proton coupled = 156 proton decoupled 200 160 120 80 40 8 (ppm) H NMR Spectrum (200 MHz, CDCI, solution) 10 8. 7 4 3 8 (ppm) % of base peak absorbance
17-19 please help
question 15
Problem 3 IR Spectrum (quid fam) etnylacetare 2984 1741 1243 4000 3000 2000 1600 1200 V (cm") 800 00P 100 43 80 Mass Spectrum 0.5- 60 UV spectrum M= 88 1.아 solvent ethanol 15 4 mg/ 10 ms path length 1.00 om 20 CAH8O2 40 80 120 160 200 240 280 200 250 300 350 m/e 2 (nm) 13C NMR Spectrum (50 0 MHz. CDCI, solution) DEPT CH, CHt CHt solvent proton decoupled 0 8 (ppm) 80 40 160 120 200 H NMR Spectrum (200 MHz, CDCI, solution) TMS 3 1 8 (ppm) 4 8 9. 10 % of base peak
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