3458 Problem 9 115 IR Spectrum (CO solution 4000 100 282 2 20 80 % of base peak W 3000 2000 V (cm) 59 103 1600 40 1200 600 1400 Move branch M-118 (<1%) Mass Spectrum Ho Gh C6H1402 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (100 0 MHz CDCI, solution) <- 4 =1400 2n+1=3 No significant UV absorption above 220 nm 2x61214-2)+(x2) =(12+2-12+2/14 = 12+2= 12 +4 114-14 =2016 DEPT CH CH CH proton decoupled solvent L T 200 160 120 80 40 'H NMR Spectrum (200 MHz, CDCI, solution) Exchanges with D₂O ୮ L 1451427 =148 0 8 (ppm) TMS 2 L 10 9 8 7 6 5 4 3 2 1 0 8 (pp

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Chapter1: Chemical Foundations
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Question
115
Problem 9
3458
D-H)
IR Spectrum
(CO souton
4000
3000
2000
znrl-3
1600
1200
V (cm')
800
100
80
50
Mass Spectrum
Ho Gh
Move blanc
M 118 ( 1S)
No significant UV
absorption above 220 nm c Le
103
CeH1402
40
80
120
160
200
240
280
m/e
13C NMR Spectrum
(100 O MHz CDCI, solution)
-14-14
-zare
DEPT CH CHt CH
solvent
proton decoupied
40
0 8 (ppm)
160
120
80
200
'H NMR Spectrum
(200 MHz, CDCI, solution)
Exchanges with
D20
TMS
1
8 (ppm)
4.
3
7
6.
8.
10
98
Sof base peak
Transcribed Image Text:115 Problem 9 3458 D-H) IR Spectrum (CO souton 4000 3000 2000 znrl-3 1600 1200 V (cm') 800 100 80 50 Mass Spectrum Ho Gh Move blanc M 118 ( 1S) No significant UV absorption above 220 nm c Le 103 CeH1402 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (100 O MHz CDCI, solution) -14-14 -zare DEPT CH CHt CH solvent proton decoupied 40 0 8 (ppm) 160 120 80 200 'H NMR Spectrum (200 MHz, CDCI, solution) Exchanges with D20 TMS 1 8 (ppm) 4. 3 7 6. 8. 10 98 Sof base peak
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