MS: m/z: 102.1 (100.0%) and m/z =103.1 (6.5%) IR (cm-1): 3000-3300 (strong, broad), 2950; 1150 (strong); 1H NMR (8): 0.91 (6H, d, J-7 Hz), 1.19 (6H, s), 1.48 (1H, singlet disappears with D2O), 1.65 (1H, septet, J=7Hz); ** HO II III ķ IV OH ķ V

Determine the compound (name or structure) from the data. Explain features from each data  Molecular formula: C3H8O -Use molecular formula to determine IHD -IR: Identify the presence/absence of five key functional groups -NMR: Analyze this last. Consider multiplicity and peak area to confirm compound -Structure?

Do it 8c asap

The intensity of M+, M+1, and M+2 peak are 100.0, 6.8, 31.9. How many carbons are in the compound? (whole number digit only) 100 MS-NW-5495 80 60 40 10 20 30 40 50 60 70 80 90 100 110 m/z Relative Intensity 20

I. Look at the MS/MS for paracetamol (a drug), explain the peaks seen at 134 and 110, and draw the structure for the 110 peak. Paracetamòl N-(4-hydroxyphenyliacetamide ESI+, MS/MSs Kky pan_03_c80720211368 1-38 RT: 0.00024 AV 35 N: 107ES T TMSES F ms 12.00g24 00 0 00-10.0g 100g 110.0 CH но 70 (M.H]* 162.0 16 1340 130 100

The intensities of peaks at 69 m/z, 70 m/z, and 71 m/z are 1.2, 31.2, and 1.7, respectively. How many carbons does the compound have? 100 MS-N-1334 80- 40 20- 10 15 20 25 30 35 40 45 50 55 60 65 70 m/z Relative Intensity

A student performed a series of reactions and obtained the spectral data provided. The reaction sequence is shown below.. What are the structures for A, B, C, and D? Compound B NMR (relative integrated areas below peaks) CH;CH,O°N 1. BHTHF N-bromosuccnimide A CH;CH,OH B 2. H,O,/OH- D hv reflux Compound A NMR (relative integrated areas below peaks) PPM 5 Compound B IR INFRARED SPECTRUM PPM 5 1 6 0.8 Compound A IR INFRARED SPECTRUM 0.6 0.8 0.4 0.4 0.2- 3000 2000 Wavenumber (cm-1) 1000 The MS of compound B shows an M+ peak at 198 and an M+2 peak at 200 with a relative abundance of 1:0.97 2000 Wavenumber (cm-1) 3000 1000 Transmitance Relative Transmittance

The intensity of M+, M+1, and M+2 peak are 100.0, 6.8, 31.9. The compound contains carbons, hydrogens, and a heteroatom. What is the molecular formula of the compound? (use format CxHyZ, where Z is heteroatom) 100 MS-NW-549S 80 60 40 10 20 30 40 50 60 70 80 90 100 110 Relative Intensity 20

Assign the peaks in the spectrum to the functional groups in n-butyl acetate. Microns (µm) 2.5 3.0 3.5 4.0 5.0 6.0 8 10 15 20 100 a 2787 cm-1 1083 cm-1 2965 cm- 1742 cm 1246 cm-1 4000 3500 3000 2500 2000 1500 1000 500 Wavenumber (cm1) C=O peak =| С-Н рeak C-O peak Submit Transmittance (%)

1.37 Calculate the Unsaturation Index of each Compound ( b = 1.37 ppm, resonances singlet, 9H Compound 17a. C,H,,O2 Unsat. Index (2C + 2 - H - X + N)/2 = Ja=11.28 ppm, singlet, 1H 8, ppm 11.28 2.5 2.0 1.5 3.5 3.0 5.5 5.0 4.5 4.0 8.0 7.5 7.0 6.5 6.0 of 12.0 11.5 11.0 10.5 10.0 9.5 9.0 8.5 1) SOCI2; 2) NH3 (excess) 3) Br2, NaOH, H2O 1.15 b = 1.15 ppm, singlet, 9H Compound 17b. C,H,,N Unsat. Index = (2C + 2 - H - X + N)/2 = a = 3.96 ppm, 1 singlet, 2H 8, ppm 3.96 10.5 10.0 9.5 9.0 8.5 8.0 7.5 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 8 in