Problem 14IR Spectrum(iquid fim)120335440003000200016001200800v (cm")10045Mass Spectrum8060No significant UVabsorption above 220 nmM**= 60 (* 1%)C3H&O4080120m/e16020024028013C NMR Spectrum(50 0 MHz, CDCI, solution)proton coupledsolventproton decoupled20016012080408 (ppm)H NMR Spectrum(200 MHr. CDCI, solution)1-1expansionsTMS1.51.0exchangeswith D;0454.0ppmppm106.86.4.28 (ppm)102% of base peak

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4000 8 8 8 8 8 % of base peak 100 80 3354 3000 45 IR Spectrum (liquid film) M = 60 (<1%) 120 40 13C NMR Spectrum (500 MHz, CDCI, solution) proton coupled proton decoupled 200 TH NMR Spectrum (200 MHz. CDCI, solution) 4.5 80 2000 v (cm¹) 4.0 160 m/e 160 1600 200 240 mm 1200 800 Mass Spectrum 120 expansions ppm 1.5 1.0 C3H₂O 280 solvent 80 ppm Problem 14 وصلية إلى منا No significant UV absorption above 220 nm 40 exchanges with D₂0 120 0 8 (ppm) $ TMS

4000 8 8 8 8 8 % of base peak 100 80 3354 3000 45 IR Spectrum (liquid film) M = 60 (<1%) 120 40 13C NMR Spectrum (500 MHz, CDCI, solution) proton coupled proton decoupled 200 TH NMR Spectrum (200 MHz. CDCI, solution) 4.5 80 2000 v (cm¹) 4.0 160 m/e 160 1600 200 240 mm 1200 800 Mass Spectrum 120 expansions ppm 1.5 1.0 C3H₂O 280 solvent 80 ppm Problem 14 وصلية إلى منا No significant UV absorption above 220 nm 40 exchanges with D₂0 120 0 8 (ppm) $ TMS

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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