Problem 11. The 60° strain rosette is mounted on the surface of the bracket. The following readings are obtained for each gage: Ea=-780(106), Eb = 400(10-6), and & = 500(106). Determine (a) the principal strains and (b) the maximum in-plane shear strain and associated average normal strain. In each case show the deformed element due to these strains. b C 60° a 60° Note: The strain components could be determined using the below strain transformation equations. b Вь 6a Ꮎ x 2 ε₁ = ε cos² +ε, sin² + ½ sin cos 2 y 2 ε₁ = ε cos² 0₁₂ + ε, sin² 0₂+½xy sin е, cos ɛ₁ = ɛ¸ cos² O̟ +ɛ¸, sin² € +¼¸, sin е cos 0 xy

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter7: Analysis Of Stress And Strain
Section: Chapter Questions
Problem 7.7.3P: An element of material in plain strain is subjected to shear strain xy = 0.0003. (a) Determine the...
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Problem 11. The 60° strain rosette is mounted on the surface of the bracket.
The following readings are obtained for each gage:
Ea=-780(106), Eb = 400(10-6), and & = 500(106).
Determine (a) the principal strains and (b) the maximum in-plane shear strain and associated
average normal strain. In each case show the deformed element due to these strains.
b
C
60°
a
60°
Note: The strain components could be determined using the below strain transformation equations.
b
Вь
6a
Ꮎ
x
2
ε₁ = ε cos² +ε, sin² + ½ sin cos
2
y
2
ε₁ = ε cos² 0₁₂ + ε, sin² 0₂+½xy
sin е, cos
ɛ₁ = ɛ¸ cos² O̟ +ɛ¸, sin² € +¼¸, sin е cos 0
xy
Transcribed Image Text:Problem 11. The 60° strain rosette is mounted on the surface of the bracket. The following readings are obtained for each gage: Ea=-780(106), Eb = 400(10-6), and & = 500(106). Determine (a) the principal strains and (b) the maximum in-plane shear strain and associated average normal strain. In each case show the deformed element due to these strains. b C 60° a 60° Note: The strain components could be determined using the below strain transformation equations. b Вь 6a Ꮎ x 2 ε₁ = ε cos² +ε, sin² + ½ sin cos 2 y 2 ε₁ = ε cos² 0₁₂ + ε, sin² 0₂+½xy sin е, cos ɛ₁ = ɛ¸ cos² O̟ +ɛ¸, sin² € +¼¸, sin е cos 0 xy
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