PROBLEM 1: To determine the effect of a growth stimulant, 24 feedlot beef cattle were randomly assigned to three groups at eight per group. Cattles in group 3 were given an injection of 10 units of a growth hormone, cattle in group 2 received an injection of 5 units, and group 1 received no injection. The cattle are of the same breed and age and were fed identically at the same location. The weight gained, in pounds, were recorded after a specified period. 1. Give a possible randomization layout of the experiment. Specify legends if there is any. 2. Cite requisites of the experimental condition in the context of the problem for the completely randomized design to be a valid design. Explain your answer.
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- Penicillin is produced by the Penicillium fungus, which is grown in a broth whose sugar content must be carefully controlled. Several samples of broth were taken on three successive days, and the amount of dissolved sugars, in milligrams per milliliter, was measured on each sample. The results were as follows. Day 1 : 5.2 5.5 5.1 4.9 5.3 5.0 5.2 5.1 5.4 5.2 4.8 5.1 5.4 Day 2 : 5.8 5.1 5.3 5.5 5.2 4.9 5.4 5.0 5.4 5.0 5.6 5.4 5.6 Day 3 : 5.9 4.9 5.2 5.3 5.1 5.4 5.3 5.8 5.5 5.4 5.4 5.4 5.2 Can you conclude that the mean sugar concentration differs among the three days? Use the =α0.05 level of significance and the ANOVA table shown below. One-way ANOVA: Sugar Concentration Source DF SS MS F P Days 2 0.2851 0.1426 2.3135 0.1134 Error 36 2.2185 0.0616…Fill in the blanks in the following source tables... Is F significant? If it is significant, at what alpha level?2h. How long it takes paint to dry can have an impact on the production capacity of a business. An auto body & paint business invested in a paint-drying robot to speed up its process. An interesting question is, "Do all paint-drying robots have the same drying time?" To test this, suppose we sample five drying times for each of different brands of paint-drying robots. The time in minutes until the paint was dry enough for a second coat to be applied was recorded. Suppose the following data were obtained. Robot 1 Robot 2 Robot 3 Robot 4 127 145 134 149 137 133 144 141 135 143 137 136 125 146 137 141 141 128 128 153 Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value =
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- Do lizards play a role in spreading plant seeds? Some research carried out in a country would suggest so. The researchers collected 400 seeds of this particular type of fig, 100 of which were from each treatment: lizard dung, bird dung, rock hyrax dung, and uneaten figs. They planted these seeds in batches of 5, and for each group of 5 they recorded how many of the seeds germinated. This resulted in 20 observations for each treatment. The treatment means and standard deviations are given in the accompanying table. Treatment n Uneaten figs 20 2.80 0.30 Lizard dung 20 2.75 0.37 Bird dung 20 2.10 0.35 Hyrax dung 20 1.85 0.26 n USE SALT (a) Construct the appropriate ANOVA table, and test the hypothesis that there is no difference between the means for the number of seeds germinating for the four treatments. (Use a = 0.05. Round your mean squares to three decimal places and F statistic to two decimal places.) Source of Sum of Mean df Variation Squares Square Treatments 3 26.25 8.750 83.93…Do lizards play a role in spreading plant seeds? Some research carried out in a country would suggest so. The researchers collected 400 seeds of this particular type of fig, 100 of which were from each treatment: lizard dung, bird dung, rock hyrax dung, and uneaten figs. They planted these seeds in batches of 5, and for each group of 5 they recorded how many of the seeds germinated. This resulted in 20 observations for each treatment. The treatment means and standard deviations are given in the accompanying table. Treatment Uneaten figs 20 2.80 0.30 Lizard dung 20 2.75 0.36 Bird dung 20 2.10 0.35 Hyrax dung 20 1.85 0.29 n USE SALT (a) Construct the appropriate ANOVA table, and test the hypothesis that there is no difference between the means for the number of seeds germinating for the four treatments. (Use a = 0.05. Round your mean squares to three decimal places and F statistic to two decimal places.) Source of Variation Sum of Squares Mean df Square 3 13.45 4.483333 42.08 Treatments…Do lizards play a role in spreading plant seeds? Some research carried out in a country would suggest so. The researchers collected 400 seeds of this particular type of fig, 100 of which were from each treatment: lizard dung, bird dung, rock hyrax dung, and uneaten figs. They planted these seeds in batches of 5, and for each group of 5 they recorded how many of the seeds germinated. This resulted in 20 observations for each treatment. The treatment meens and standard deviations are given in the accompanying table. Treatment n x Uneaten figs 20 2.50 0.30 Lizard dung 20 2.45 0.35 Bird dung 20 1.80 0.37 |Нуrах dung 20 1.550.29 A USE SALT (a) Construct the appropriate ANOVA table, and test the hypothesis that there is no difference between the means for the number of seeds germinating for the four treatments. (Use a = 0.0S. Round your mean squares to three decimal places and F statistic to two decimal places.) Sum of Squares Source of Mean df Variation Square Treatments Error Total Use…
- Do lizards play a role in spreading plant seeds? Some research carried out in a country would suggest so. The researchers collected 400 seeds of this particular type of fig, 100 of which were from each treatment: lizard dung, bird dung, rock hyrax dung, and uneaten figs. They planted these seeds in batches of 5, and for each group of 5 they recorded how many of the seeds germinated. This resulted in 20 observations for each treatment. The treatment means and standard deviations are given in the accompanying table. Treatment n Uneaten figs 20 | 2.80 0.30 Lizard dung 20 2.75 0.36 Bird dung 20 2.10 0.35 Hyrax dung 20 1.85 0.29 n USE SALT (a) Construct the appropriate ANOVA table, and test the hypothesis that there is no difference between the means for the number of seeds germinating for the four treatments. (Use a = 0.05. Round your mean squares to three decimal places and F statistic to two decimal places.) Source of Variation Sum of Squares Mean df F Square Treatments 3 13.45 4.483333…Do lizards play a role in spreading plant seeds? Some research carried out in a country would suggest so. The researchers collected 400 seeds of this particular type of fig, 100 of which were from each treatment: lizard dung, bird dung, rock hyrax dung, and uneaten figs. They planted these seeds in batches of 5, and for each group of 5 they recorded how many of the seeds germinated. This resulted in 20 observations for each treatment. The treatment means and standard deviations are given in the accompanying table. Treatment x S Uneaten figs 20 2.80 0.30 Lizard dung 20 2.75 0.36 Bird dung 20 2.10 0.35 Hyrax dung 20 1.85 0.29 USE SALT (a) Construct the appropriate ANOVA table, and test the hypothesis that there is no difference between the means for the number of seeds germinating for the four treatments. (Use a = 0.05. Round your mean squares to three decimal places and F statistic to two decimal places.) Source of df Sum of Squares Mean Square F Variation Treatments Error Total Use…You want to determine the effect of soap on bacterial colonies. In order to make sure that the environmentdoes not affect your experiment, you divide 13 different petri dishes in half - one side is exposed to soap, theother is a control.You measure the number of colonies that grow in each petri dish and come up with the following results:petri dish 1 2 3 4 5 6 7 8 9 10 11 12 13soap 10 5 7 10 19 11 13 17 19 8 11 10 16control 20 17 11 17 26 18 21 25 24 17 17 17 21Perform a complete hypothesis test to see if there is a difference in bacterial colonies between the soapand control dishes.Again - notice that you are given no advice. You need to figure this out on your own, althoughthis one should be a bit easier than (4). Feel free to use R to solve this problem, just make sureyou don't just hand in a printout.