Problem #1: The steel shaft is made of two segments, AC has a diameter of 12 mm and CB has a diameter of 25 mm. if it is fixed at ends A & B and subjected to a torque of 750 N.m. Determine the maximum shear stress in the shaft. Gst = 75 GPa. A 12 mm 125 mm D 750 N-m 200 mm 25 mm B 300 mm 750 N- m Equilibrium: Тл + Tв - 750 %3D0 (1) Compatibility condition: ØD/A = OD/B TA(125) + ТА(200) Тв(300) %3D F(6')G ' {12.5*)G¯ {(12.5')G 10463TĄ = 12288TB (2) Solving Eqs. (1) and (2) yields TA = 78.82 N · m Tg = 671.18 N m Tc 78.82(10°)(6) TAC = = 232.3 MPa (max) Ans. 3(6") Tc 671.18(10*)(12.5) TDB = 218.77 MPa {(12.54)

Problem #1: The steel shaft is made of two segments, AC has a diameter of 12 mm and CB has a diameter of 25 mm. if it is fixed at ends A & B and subjected to a torque of 750 N.m. Determine the maximum shear stress in the shaft. Gst = 75 GPa. A 12 mm 125 mm D 750 N-m 200 mm 25 mm B 300 mm 750 N- m Equilibrium: Тл + Tв - 750 %3D0 (1) Compatibility condition: ØD/A = OD/B TA(125) + ТА(200) Тв(300) %3D F(6')G ' {12.5)G¯ {(12.5')G 10463TĄ = 12288TB (2) Solving Eqs. (1) and (2) yields TA = 78.82 N · m Tg = 671.18 N m Tc 78.82(10°)(6) TAC = = 232.3 MPa (max) Ans. 3(6") Tc 671.18(10)(12.5) TDB = 218.77 MPa {(12.54)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

Please explain what is the deformation of D/A = deformation of D/B Or Why is deformation D/A - deformation D/B=0

Problem #1: The steel shaft is made of two segments, AC has a diameter of 12 mm and CB
has a diameter of 25 mm. if it is fixed at ends A & B and subjected to a torque of 750 N.m.
Determine the maximum shear stress in the shaft. Gst = 75 GPa.
A
12 mm
125 mm
D
750 N•m
200 mm
25 mm
В
300 mm
750 N. m
Equilibrium:
ТА+ Тв - 750 — 0
(1)
Compatibility condition:
OD/A = $p/B
DB
TẠ(125)
ТА(200)
Тв(300)
3(6*)& * (12,5*)&¯ (12.5*)G
10463TA = 12288TB
(2)
Solving Eqs. (1) and (2) yields
TA = 78.82 N · m
TB = 671.18 N · m
Tc 78,82(10*)(6)
TAC =
= 232.3 MPa (max)
Ans.
%3D
Tc 671.18(10*)(12.5)
(12.54)
TDB
J
= 218.77 MPa

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