Problem 1: Initially, the switch in Fig 1. is in its position A and capacitors C₂ and C3 are uncharged. Then the switch is flipped to position B. Afterward, what are the charge on and the potential dif- ference across each capacitor? Partial answer: AV₁ = 55 V, AV₂ = 33.5 V. a) While the capacitor is in position A, as shown in Fig.1, com- Switch + 100V A C₁ =ISμF LC₁₂=20μF -C3=30μF
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An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
Hello,
I am having trouble with PART B, PART C AND PART D , IS THERE ANY CHANCE YOU CAN HELP ME WITH THOSE PROBLEMS I KEEP GETTING THE WRONG ANSWER, CAN YOU LABEL WHICH ONE IS WHICH. Thank you

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