Hello, I keep getting the wrong answer for each part of this problem, can you help me with PART A,PART B AND Part C and can you label which one is which and go step by step so I can understand what I did wrong. thank you Problem 1: Initially, the switch in Fig 1. is in its position A andcapacitors C₂ and C3 are uncharged. Then the switch is flipped toposition B. Afterward, what are the charge on and the potential dif-ference across each capacitor?Partial answer: AV₁ = 55 V, AV₂ = 33.5 V.a) While the capacitor is in position A, as shown in Fig.1, com-pute the charge Q accumulated on the plates of the capacitor C₁.b) After the switch is flipped to the position B, the battery is no longerconnected to the contour and the charge redistributes between the ca-pacitors as shown in Fig.2. Notice that I used the fact that the segmentbetween the capacitors C₂ and C3 has to be neutral (therefore, they havethe same charge), but the segments connecting C₁ to C₂ and C₁ to C3 arenot neutral. What can you say about the sum of charges Q₁ and Q₂?Switch100VAC₁B100VLC₁₂2= 20 μFт Cз=30MFISHFFIG. 1: The scheme for Problem 1Q₁-Q₁Q2-=-=T-Q₂Q2Q2-T-Q₂FIG. 2: The scheme for Problem 1bc) Use Kirchhoff's loop law to get another relation between charges Q₁ and Q2. Starting from point Bin Fig.2, move counterclockwise along the loop and register the potential differences that you encounterwhen crossing the capacitors (pay attention to the signs - when you move from a positively charged to anegatively charged plate, the potential is decreasing). The sum of all potential differences has to be zero.d) You answers to parts b) and c) give you a system of two equations that you can solve to find individualvalues of charges Q₁ and Q2. Solve it to find the values of the charges, and then compute the potentialdifferences across each capacitor.

Answered: Image /qna-images/answer/44ab86b8-59fe-422d-b3d7-af5429789ac0.jpg

Answered: Problem 1: Initially, the switch in Fig…

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