Could you check my work from 1-5? I understand if you cannot do all questions, would just appreciate whatever you are allowed to do. Thanks! AP PhysicsDate:1. When a pitcher throws a curve ball, the ball is given a fairly rapid spin. If a 0.15-kg baseball with aradius of 3.7 cm is thrown with a linear speed of 48 m/s and an angular speed of 42 rad/s, what is thekinetic energy of the ball? Assume the ball is a uniform, solid sphere.1 ² mr²k=1/√² + 1² =²²2² =²..15. 037 = .00222 k = 1.15-48² +1 00222-42²174.758J= 172.8+1.958TTouiem setr=1.22-5. A propeller (arm length 1.2 m) starts from rest and begins to rotate counterclockwise with aconstant angular acceleration 2.7 rad/s².A2. How long will it take for the propeller's angular velocity to reach 5.7 rad/s?2.7.t=5.7 (t = 2.115)3. What is the linear velocity of the tip of the propeller at 5.7 rad/s?V=rw1.2-5.7= (6.84 m/s4. What is the tangential acceleration of the tip of the propeller at this time?b2-27 ay ngaa=ra79₁ ====5. What is the radial (also called centripetal) acceleration of the tip of the propeller at this time?26.84/1.2 38.988N6. Consider a particle of mass m = 22.0 kg revolving around an axis with aconstant angular velocity of 6.00 rad/s. The perpendicular distance fromthe particle to the axis is r=0.750 m. What is the kinetic energy of theparticle?P

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1. When a pitcher throws a curve ball, the ball is given a fairly rapid spin. If a 0.15-kg baseball with a radius of 3.7 cm is thrown with a linear speed of 48 m/s and an angular speed of 42 rad/s, what is the kinetic energy of the ball? Assume the ball is a uniform, solid sphere. 2 k={/m² ² + 1 ² ] = ³/2mr ² 1=²..15.037 = .00222 k=15-48² +00222-421 = 172.8+1.958 = 174.758 J r=1.2 2-5. A propeller (arm length 1.2 m) starts from rest and begins to rotate counterclockwise with a constant angular acceleration 2.7 rad/s². 2. How long will it take for the propeller's angular velocity to reach 5.7 rad/s? 2.7-t=5.7 (t= 2.11s 3. What is the linear velocity of the tip of the propeller at 5.7 rad/s? v=rw 1.2-5.7= (6.84 m/s 4. What is the tangential acceleration of the tip of the propeller at this time? 1.2.2.7 = (3.24/2 a=ra 5. What is the radial (also called centripetal) acceleration of the tip of the propeller at this time? 2 9₁== 6.84/1.238.988N 6. Consider a particle of mass m = 22.0 kg revolving around an axis with a constant angular velocity of 6.00 rad/s. The perpendicular distance from the particle to the axis is r=0.750 m. What is the kinetic energy of the particle? 2

1. When a pitcher throws a curve ball, the ball is given a fairly rapid spin. If a 0.15-kg baseball with a radius of 3.7 cm is thrown with a linear speed of 48 m/s and an angular speed of 42 rad/s, what is the kinetic energy of the ball? Assume the ball is a uniform, solid sphere. 2 k={/m² ² + 1 ² ] = ³/2mr ² 1=²..15.037 = .00222 k=15-48² +00222-421 = 172.8+1.958 = 174.758 J r=1.2 2-5. A propeller (arm length 1.2 m) starts from rest and begins to rotate counterclockwise with a constant angular acceleration 2.7 rad/s². 2. How long will it take for the propeller's angular velocity to reach 5.7 rad/s? 2.7-t=5.7 (t= 2.11s 3. What is the linear velocity of the tip of the propeller at 5.7 rad/s? v=rw 1.2-5.7= (6.84 m/s 4. What is the tangential acceleration of the tip of the propeller at this time? 1.2.2.7 = (3.24/2 a=ra 5. What is the radial (also called centripetal) acceleration of the tip of the propeller at this time? 2 9₁== 6.84/1.238.988N 6. Consider a particle of mass m = 22.0 kg revolving around an axis with a constant angular velocity of 6.00 rad/s. The perpendicular distance from the particle to the axis is r=0.750 m. What is the kinetic energy of the particle? 2

Inquiry into Physics

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Publisher:Ostdiek

Chapter3: Energy And Conservation Laws

Section: Chapter Questions

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Question

Could you check my work from 1-5? I understand if you cannot do all questions, would just appreciate whatever you are allowed to do. Thanks!

AP Physics
Date:
1. When a pitcher throws a curve ball, the ball is given a fairly rapid spin. If a 0.15-kg baseball with a
radius of 3.7 cm is thrown with a linear speed of 48 m/s and an angular speed of 42 rad/s, what is the
kinetic energy of the ball? Assume the ball is a uniform, solid sphere.
1 ² mr²
k=1/√² + 1² =
²²2² =²..15. 037 = .00222 k = 1.15-48² +1 00222-42²
174.758J
= 172.8+1.958
TTouiem set
r=1.2
2-5. A propeller (arm length 1.2 m) starts from rest and begins to rotate counterclockwise with a
constant angular acceleration 2.7 rad/s².
A
2. How long will it take for the propeller's angular velocity to reach 5.7 rad/s?
2.7.t=5.7 (t = 2.115)
3. What is the linear velocity of the tip of the propeller at 5.7 rad/s?
V=rw
1.2-5.7= (6.84 m/s
4. What is the tangential acceleration of the tip of the propeller at this time?
b2-27 ay nga
a=ra
7
9₁ ====
5. What is the radial (also called centripetal) acceleration of the tip of the propeller at this time?
2
6.84/1.2 38.988N
6. Consider a particle of mass m = 22.0 kg revolving around an axis with a
constant angular velocity of 6.00 rad/s. The perpendicular distance from
the particle to the axis is r=0.750 m. What is the kinetic energy of the
particle?
P

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