Question 14 Assume that a prvadure yields a witha fral binomal distrb ution eputed n= 13 times, ilse the binomial probabilits formula to find the probabult 2 De probabilit g= o-53 on a Report beli K=2 gwen K%3D2 A ingle trial answer accurate to 4 dicimal places. %3D Answer
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- Q23.) These are the daily production rates for a sample of production line worker as well as their before and after.Let d = After - Before. Worker Before After 1 6 9 2 10 12 3 9 10 4 8 11 5 7 9 Was the training program effective? Give the hypotheses for this problem. Compute the test statistic. At a = .01, test the hypotheses. Did the training program increase the production rates? Please don't use a calculator, I want to know how to do this through equations.9/9 what is the P value for this test? Round to three decimal places as needed. make a statement regarding the null hypothesis and draw a conclusion for this test.Item5 Time Remaining 56 minutes 33 seconds 00:56:33 eBook Item 5 Time Remaining 56 minutes 33 seconds 00:56:33 The null and alternate hypotheses are:H0 : μd ≤ 0H1 : μd > 0The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of 4 days last month. Day 1 2 3 4 Day shift 11 12 13 19 Afternoon shift 9 9 10 15 At the 0.05 significance level, is there a difference in the mean number of citations given by the two shifts?a. What is the p-value? (Round your answer to 4 decimal places.) b. What is your decision regarding the null hypothesis?multiple choice Reject H0 Do not reject H0 c. What is the conclusion indicated by the analysis?
- Suppose n =42 and p=0.341 Question 15 of 15 suonsano 13. 14. 15. OA large automobile insurance company selected samples of single and married male policyholders and recorded the number who made an insurance claim over the preceding three-year period. Single Policyholders Married Policyholders n1 = 390 n2 = 860 Number making claims = 78 Number making claims = 129 a. Use a = 0.05. Test to determine whether the claim rates differ between single and married male policyholders. z-value (to 2 decimals) p-value (to 4 decimals) We Select your answer - v that there is the difference between claim rates. b. Provide a 95% confidence interval (to 4 decimals) for the difference between the proportions for the two populations. Enter negative answer as negative number. 0= Icon Key « Question 15 of 154. At the 0.05 level, can we conclude there is a difference between the students’ fall weight and spring weight? Draw a random sample from the 67 college students, carefully explaining your procedure. YOU MUST USE a different “random” method this time your sample must consist of 10 students, not 20-29 Determine whether your sample provides statistical evidence that there is a difference between the students’ fall weight (before) and spring weight (after). Set alpha at 0.05. Adding on to the written report above, address question 4! o Note: It may be wise to use a hypothesis testing sheet (nice handwriting, etc…) to help with your report.
- A simple random sample of size n=15 is drawn from a population that is normally distributed. The sample mean is found to be x=21.1 and the sample standard deviation is found to be s=6.3. Determine if the population mean is different from 24 at the a=0.01 level of significance. Complete parts (a) through (d) below. (a) Determine the null and alternative hypotheses. Ho: H₁B 24 24 AA survey of 22552255 randomly selected US adults found that 51%51% said they know all or most of their neighbors.1 Does this provide evidence that more than half of US adults know most or all of their neighbors? Clearly state the null and alternative hypotheses. Calculate the test statistic and pp-value.Round your answer for the test statistic to two decimal places, and your answer for the pp-value to three decimal places.test statistic == pp-value == Can we conclude that more than half of US adults know most or all of their neighbors? Yes NoA random sample of 90 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.79. (1) Test Ho : p = 0.5 against H. : p > 0.5. Use a = 0.01. test statistic z = critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.5. O B. We can reject the null hypothesis that p = 0.5 and accept that p > 0.5. %3D (2) Test Ho : p = 0.55 against H. : p < 0.55. Use a = 0.05. test statistic z = critical z score The final conclusion is A. We can reject the null hypothesis that p B. There is not sufficient evidence to reject the null hypothesis that p = 0.55. 0.55 and accept that p < 0.55. (3) Test Ho : p = 0.6 against Ha:p # 0.6. Use a = 0.05. test statisticz = positive critical z score negative critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.6. B. We can reject the null hypothesis that p = 0.6 and accept that p #…
- e this K 23-2....xlsx ^ Assume that you have a sample of n₁ = 7, with the sample mean X₁ = 43, and a sample standard deviation of S₁ = 5, and you have an independent sample of n₂ = 16 from another population with a sample mean of X₂ = 31, and the sample standard deviation S₂ = 8. Construct a 90% confidence interval estimate of the population mean difference between ₁ and μ2. Assume that the two population variances are equal. ₁-₂ (Round to two decimal places as needed.) View an example Get more help. data-2_13_2023-2....xlsx ^ ... (0,0) Clear all More- Check answer Show all X ►G baby buster - Google Search ses.cscc.edu/webapps/assessment/take/launch.jsp?course_assessment_id%=_804647_1&course_id%3D_172595_1&content_idD Question Completion Status: QUESTION 8 Given a binomial distribution where n=90 and p-0.46. Which of the following is considered an unusual event? O P(x=32) O P(x=49) O P(x=31) O P(x=50)ONLY Q15
