Item5 Time Remaining 56 minutes 33 seconds00:56:33 eBookItem 5 Time Remaining 56 minutes 33 seconds00:56:33The null and alternate hypotheses are:H0 : μd ≤ 0H1 : μd > 0The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of 4 days last month. Day1234Day shift11121319Afternoon shift991015At the 0.05 significance level, is there a difference in the mean number of citations given by the two shifts?a. What is the p-value? (Round your answer to 4 decimal places.) b. What is your decision regarding the null hypothesis?multiple choiceReject H0Do not reject H0c. What is the conclusion indicated by the analysis?

We have given that Sample size n=4 The null and alternate hypotheses are:H0 : μd ≤ 0H1 : μd > 0 Solution:- Sample 1 Sample 2 Difference = Sample 1 - Sample 2 11 9 2 12 9 3 13 10 3 19 15 4 Average 13.75 10.75 3 St. Dev. 3.594 2.872 0.816 n 4 4 4

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Item 5

Time Remaining 56 minutes 33 seconds

00:56:33

The null and alternate hypotheses are:

H₀ : μ_d ≤ 0

H₁ : μ_d > 0

The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of 4 days last month.

	Day
1	2	3	4
Day shift	11	12	13	19
Afternoon shift	9	9	10	15

At the 0.05 significance level, is there a difference in the mean number of citations given by the two shifts?

a. What is the p-value? (Round your answer to 4 decimal places.)

b. What is your decision regarding the null hypothesis?

multiple choice