A random sample of 90 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.79. (1) Test Ho : p = 0.5 against H:p> 0.5. Use a = 0.01. test statistic z = critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.5. O B. We can reject the null hypothesis that p = 0.5 and accept that p > 0.5. (2) Test Ho : p= 0.55 against H.: p< 0.55. Use a = 0.05. test statisticz = critical z score The final conclusion is A. We can reject the null hypothesis that p = 0.55 and accept that p < 0.55. O B. There is not sufficient evidence to reject the null hypothesis that p == 0.55. (3) Test Ho : p= 0.6 against H.: p+ 0.6. Use a = 0.05. test statisticz = positive critical z score negative critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.6. B. We can reject the null hypothesis that p = 0.6 and accept that p + 0.6.

A random sample of 90 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.79. (1) Test Ho : p = 0.5 against H:p> 0.5. Use a = 0.01. test statistic z = critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.5. O B. We can reject the null hypothesis that p = 0.5 and accept that p > 0.5. (2) Test Ho : p= 0.55 against H.: p< 0.55. Use a = 0.05. test statisticz = critical z score The final conclusion is A. We can reject the null hypothesis that p = 0.55 and accept that p < 0.55. O B. There is not sufficient evidence to reject the null hypothesis that p == 0.55. (3) Test Ho : p= 0.6 against H.: p+ 0.6. Use a = 0.05. test statisticz = positive critical z score negative critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.6. B. We can reject the null hypothesis that p = 0.6 and accept that p + 0.6.

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Description: A random sample of 90 observations is selected from a binomial population with unknown probability of success p. The computedvalue of p is 0.79.(1) Test Ho : p = 0.5 against H. : p > 0.5. Use a = 0.01.test statistic z =critical z scoreThe final conc

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A random sample of 140 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.74. (1) Test Ho: p = 0.65 against H₁ : p > 0.65. Use a = 0.01. test statistic z = critical z score The final conclusion is A. We can reject the null hypothesis that p = 0.65 and accept that p > 0.65. B. There is not sufficient evidence to reject the null hypothesis that p = 0.65. (2) Test Ho: p = 0.65 against H₁ : p < 0.65. Use a = 0.01. test statistic z = critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p B. We can reject the null hypothesis that p = (3) Test Ho: p = 0.55 against Ha: p0.55. Use a = 0.01. test statistic Z = positive critical z score negative critical z score The final conclusion is = 0.65. 0.65 and accept that p < 0.65. A. We can reject the null hypothesis that p = 0.55 and accept that p = 0.55. B. There is not sufficient evidence to reject the null hypothesis that p…
I need help with this one, please. I need it to be step-by-step please for me to understand.
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A random sample of 90 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.79. (1) Test Ho : p = 0.5 against Ha : p > 0.5. Use a = 0.01. test statistic z = critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.5. B. We can reject the null hypothesis that p = 0.5 and accept that p > 0.5.
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