A random sample of 140 observations is selected from a binomial pulation with unknown probability of success p. The computed value of p is 0.74 Test Ho: p = 0.65 against Hap > 0.65. Use a = 0.01. st statistic z = tical z score e final conclusion is A. We can reject the null hypothesis that p = 0.65 and accept that p > 0.65.
A random sample of 140 observations is selected from a binomial pulation with unknown probability of success p. The computed value of p is 0.74 Test Ho: p = 0.65 against Hap > 0.65. Use a = 0.01. st statistic z = tical z score e final conclusion is A. We can reject the null hypothesis that p = 0.65 and accept that p > 0.65.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:A random sample of 140 observations is selected from a binomial
population with unknown probability of success p. The computed value of p is 0.74.
(1) Test Ho: p = 0.65 against H₁ : p > 0.65. Use a = 0.01.
test statistic z =
critical z score
The final conclusion is
A. We can reject the null hypothesis that p
=
0.65 and accept that p > 0.65.
B. There is not sufficient evidence to reject the null hypothesis that p = 0.65.
(2) Test Ho: p = 0.65 against H₁ : p < 0.65. Use a = 0.01.
test statistic z =
critical z score
The final conclusion is
A. There is not sufficient evidence to reject the null hypothesis that p
B. We can reject the null hypothesis that p =
(3) Test Ho: p = 0.55 against Ha: p0.55. Use a = 0.01.
test statistic Z =
positive critical z score
negative critical z score
The final conclusion is
= 0.65.
0.65 and accept that p < 0.65.
A. We can reject the null hypothesis that p = 0.55 and accept that p = 0.55.
B. There is not sufficient evidence to reject the null hypothesis that p = 0.55.
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