A random sample of 45 salespersons were asked how long, on average, they were able to talk to a potential customer. Their answers revealed a mean of 8.5 minutes with a variance of 9 minutes. If the confidence interval for the population mean is 8.5 * 0.88. What is the probability of selecting a salesperson that doesn't lie within this interval? 0.05 O 0.025 0.95 No correct answer
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- Suppose that the height of Asian males aged 35-44 in the United States is normally distributed with a standard deviation of 3 in. Jeremy takes a simple random sample of 16 such men and notices that none of them are unusually tall or unusually short. He then calculates the average of the sample to be 67 in. and is planning on using this to find a 90% z-confidence interval for the true mean height. Can Jeremy use this information to find the z-confidence interval? Complete the following sentences. The population distribution is and the population standard deviation is Therefore, the sample to find a 90% z-confidence interval.Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.The producer of a weight-loss pill advertises that people who use the pill lose, after one week, an average (mean) of 1.8 pounds with a standard deviation of 1.05 pounds. In a recent study, a group of 45 people who used this pill were interviewed. The study revealed that these people lost a mean of 1.73 pounds after one week. If the producer's claim is correct, what is the probability that the mean weight loss after one week on this pill for a random sample of 45 individuals will be 1.73 pounds or more? Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
- The producer of a weight-loss pill advertises that people who use the pill lose, after one week, an average (mean) of 1.75 pounds with a standard deviation of 1.02 pounds. In a recent study, a group of 60 people who used this pill were interviewed. The study revealed that these people lost a mean of 1.9 pounds after one week. If the producer's claim is correct, what is the probability that the mean weight loss after one week on this pill for a random sample of 60 individuals will be 1.9 pounds or less? Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.For a standardized psychology examination intended for psychology majors, the historical data show that scores have a mean of 515 and a standard deviation of 170. The grading process of this year's exam has just begun. The mean score of the 35 exams graded so far is 518. What is the probability that a sample of 35 exams will have a mean score of 518 or more if the exam scores follow the same distribution as in the past? Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.The producer of a weight-loss pill advertises that people who use the pill lose, after one week, an average (mean) of 1.8 pounds with a standard deviation of 0.95 pounds. In a recent study, a group of 45 people who used this pill were interviewed. The study revealed that these people lost a mean of 1.92 pounds after one week. If the producer's claim is correct, what is the probability that the mean weight loss after one week on this pill for a random sample of 45 individuals will be 1.92 pounds or less? Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
- The mean weight of an adult is 71 kilograms with a variance of 100. If 181 adults are randomly selected, what is the probability that the sample mean would differ from the population mean by less than 1.2 kilograms? Round your answer to four decimal places.Do male and female servers work the same number of hours? A sample of 14 female servers worked an average of 27 hours per week, with a standard deviation of 4. A sample of 23 male servers worked an average of 35 hours per week, with a standard deviation of 3. Construct a 80% confidence interval for the mean difference in hours worked for male and female servers. Assume that the populations are normal with unequal variances. Round your answers to three decimal places, and use four decimal places for any interim calculations. Hint: Think about the formula for the confidence interval. How do we find to? How do we find the standard error given that we are assuming unequal variances? We are 80% confident that the interval (-9.672 -6.328 μ₁ −μ2 in hours worked between male and female servers. Which of the following do you conclude? contains the true mean difference Female servers work more hours on average. O Male servers work more hours on average. Female and male servers work about the…A random sample of 40 college students has a mean earnings of $3120 with a standard deviation of $677 over the summer months. Determine whether a normal distribution or a t-distribution should be used or whether neither of these can be used to construct a confidence interval. Question 2 options: Cannot use normal distribution or t-distribution. Use normal distribution. Use the t-distribution.
- Do male and female servers work the same number of hours? A sample of 14 female servers worked an average of 27 hours per week, with a standard deviation of 4. A sample of 23 male servers worked an average of 35 hours per week, with a standard deviation of 3. Construct a 80% confidence interval for the mean difference in hours worked for male and female servers. Assume that the populations are normal with unequal variances. Round your answers to three decimal places, and use four decimal places for any interim calculations. We are 80% confident that the interval ( μ₁ −μ₂ in hours worked between male and female servers. contains the true mean differenceA psychologist has developed a new test to measure depression. Using a very large group of "normal" individuals, the mean score on this test is found to be p=55 and a population standard of o=12. The scores form a normal distribution. A researcher would like to use this test to evaluate a theory predicting that increased depression is a common part of the aging process. To test the theory, a sample of n=36 elderly people is obtained. The depression test is administered to each person, and the mean score for the sample is 59. Testing the hypothesis using a one-tailed test at 0.05 level of significance, do these data support the theory? You can answer "Yes" or "No". Do the 4-step process to determine the answer. Answer: