Question 2What does this recursive method do?private int Count(Node node){if (node == null)return 0;if (node.left == null && node.right == null)return 1;elsereturn Count(node.left)+ Count(node.right));}A count number of nodes that has one child in the binary tree(B) count number of nodes in the binary treeC count number of nodes that has two children in the binary treeD) count number of leaf nodes in the binary tree

As per e given code If(node == null) return 0; if (node.left== null && node.right ==…

Answered: private int Count(Node node) { if (node…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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The following code prints out all permutations of the string generate. Insert the missing statement. public class PermutationGeneratorTester { public static void main(String[] args) { PermutationGenerator generator = new PermutationGenerator("generate"); ArrayList<String> permutations = generator.getPermutations(); for (String s : permutations) { ____________________ } } }
def is_balanced(root): return __is_balanced_recursive(root) def __is_balanced_recursive(root): """ O(N) solution """ return -1 != __get_depth(root) def __get_depth(root): """ return 0 if unbalanced else depth + 1 """ if root is None: return 0 left = __get_depth(root.left) right = __get_depth(root.right) if abs(left-right) > 1 or -1 in [left, right]: return -1 return 1 + max(left, right) # def is_balanced(root):# """# O(N^2) solution# """# left = max_height(root.left)# right = max_height(root.right)# return abs(left-right) <= 1 and is_balanced(root.left) and# is_balanced(root.right) # def max_height(root):# if root is None:.
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What happens when a programmer attempts to access a node's data fields when the node variable refers to None? How do you guard against it? *PYTHON
For any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a comma (no spaces). Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 20,30, 1 #include 2 3 int main(void) { const int SIZE_LIST = 4; int keysList[SIZE_LIST]; int itemsList[SIZE_LIST]; int i; 4 6 7 8 scanf("%d", &keysList[0]); scanf ("%d", &keysList[1]); scanf("%d", &keysList[2]); scanf("%d", &keysList[3]); 10 11 12 13 scanf ("%d", &itemsList[0]); scanf ("%d", &itemsList[1]); scanf("%d", &itemsList[2]); scanf ("%d", &itemsList[3]); 14 15 16 17 18 19 /* Your code goes here */ 20 21 printf("\n"); 22 23 return 0; 24 }
Can you help me with a C++ programming task I am trying to complete for myself please: Write a program (in main.cpp) that: Prompts the user for a filename containing node data. Outputs the minimal spanning tree for a given graph. You will need to implement the createSpanningGraph method in minimalSpanTreeType.h to create the graph and the weight matrix. There are a few tabs: main.cpp, graphType.h, linkedList.h, linkedQueue.h, queueADT.h, minimalSpanTreeType.h, and then two data files labeled: CH20_Ex21Data.txt, CH20Ex4Data.txt
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private int Count(Node node) { if (node == null) return 0; if (node.left == null && node.ri return 1: else