Previous Page 20 of 28 Next → The equilibrium constant for the following reaction is 77.3 at a certain temperature. 4 A(g) + B₂(g) 3 C(g) 0.100 mol of A and 0.335 mol of B are present at equilibrium in a 5.00-L flask. What is the molar concentration of C in the flask at equilibrium? 61°F Clear Esc O A. 9.39×10 M OB. 4.26 M OC. 0.470 M O D. 8.29x10-7 M. O E. 0.137 M ⒸN F3 #3 - A F4 $ References Use the References to access important values if needed for this question. 54 % 5 QL F6 DELL FB & 7 7 F10 F11 11 F12
Previous Page 20 of 28 Next → The equilibrium constant for the following reaction is 77.3 at a certain temperature. 4 A(g) + B₂(g) 3 C(g) 0.100 mol of A and 0.335 mol of B are present at equilibrium in a 5.00-L flask. What is the molar concentration of C in the flask at equilibrium? 61°F Clear Esc O A. 9.39×10 M OB. 4.26 M OC. 0.470 M O D. 8.29x10-7 M. O E. 0.137 M ⒸN F3 #3 - A F4 $ References Use the References to access important values if needed for this question. 54 % 5 QL F6 DELL FB & 7 7 F10 F11 11 F12
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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All the back and forwth in these assignments. I am not keeping my formulas stright. Please help
Expert Solution
Step 1
Given -
4A(g)+B2(g) <->3C(g). K = 77.3
Moles of A= 0.100 mol
Moles of B2 = 0.335 mole ( There is no B hence there is mole of B2)
Volume=5.00L
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