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2. What is the mass of KIHP that you will weigh? 700-800m9 a The instructions read "Weigh out accurately 700 to 800 mg of KHP". Why are you given a range in the instructions and why is this acceplable? I+ iş acceptable because KH P is the excess reactant dnd therefore, you only need to haye ewough, moles of this compound but not a spečific number or mole's. 3. Why is it important to not have any bubbles in the tip of the buret? Dobles in the tip, of the buret becawse, of herwyise, the yvolvune of tit raut If is ivneorteut not to have äuy Actually added will be different from, the yolume to thie butet. If there are bubbles in the tip the volume of titraut thiat, act ually yets in contact with the analyte, will be lower trad the recorded Yolume. 4. How many milliliters of 6.0 M NAOH must be used to prepare 1.0 L of 0.10M NAOH? Show calculation with units. Given: M.Vi = M2 V2 Vi = M, V2 - 0.10( L V =! My = 0.10M V2 = IL M. VI = 0.014lalalah VI= I4.47 Vi= lle,47 wmL v SA student titrates a 25.00 mL aliquot of HCl (concentration unknown) with 33.10 mL of 0.1500 M NAOH. What is the concentration of HCI? Show calculation with units. HCl+ Ng OH -> HyO+ NaCI Mに 050()x ろる.10»1C M2 V2 20.1500( VI Mi= Given: you cannot use M,VI= 25 x 10- L MI ? V = 25 mL Mai 0.15,00M Mi =0.1906M M2V2 Concentration of Hel=D.1904M う」

2. What is the mass of KIHP that you will weigh? 700-800m9 a The instructions read "Weigh out accurately 700 to 800 mg of KHP". Why are you given a range in the instructions and why is this acceplable? I+ iş acceptable because KH P is the excess reactant dnd therefore, you only need to haye ewough, moles of this compound but not a spečific number or mole's. 3. Why is it important to not have any bubbles in the tip of the buret? Dobles in the tip, of the buret becawse, of herwyise, the yvolvune of tit raut If is ivneorteut not to have äuy Actually added will be different from, the yolume to thie butet. If there are bubbles in the tip the volume of titraut thiat, act ually yets in contact with the analyte, will be lower trad the recorded Yolume. 4. How many milliliters of 6.0 M NAOH must be used to prepare 1.0 L of 0.10M NAOH? Show calculation with units. Given: M.Vi = M2 V2 Vi = M, V2 - 0.10( L V =! My = 0.10M V2 = IL M. VI = 0.014lalalah VI= I4.47 Vi= lle,47 wmL v SA student titrates a 25.00 mL aliquot of HCl (concentration unknown) with 33.10 mL of 0.1500 M NAOH. What is the concentration of HCI? Show calculation with units. HCl+ Ng OH -> HyO+ NaCI Mに 050()x ろる.10»1C M2 V2 20.1500( VI Mi= Given: you cannot use M,VI= 25 x 10- L MI ? V = 25 mL Mai 0.15,00M Mi =0.1906M M2V2 Concentration of Hel=D.1904M う」

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Correct the ones that are marked wrong(2a and 5) completely and SHOW ALL CALCULATIONS:

 

2. What is the mass of KHP that you will weigh? 700-807m9 aThe instructions read "Weigh out accurately 700 to 800 tng of KHP". Why are you given a range in the instructions and why is this acceptable? It is acceptable because KH P is the excess reactaint dnd theref ure, you only need to haye enough. moles of this compound but speritic not a spečific number or mole's. Why is it important to not have any bubbles in the tip of the buret? ubles inthe tip It is, ivmeortaut not to have of the outet becawe, ot hervyise, the yolvune of fit raut actuaily Added will Sof titrant that can be written acording to the buret. If there are bubbles in the tip ofuthe buret, the volume of titrant that, actvally cts in contact with the analyte, will be lower trad thie recorded Any dif ferent from the yolume volume. How 4. many milliliters of 6.0 M NAOH must be used to prepare 1.0 L of 0.10 M NaOH? Show calculation with units. Given: MiV, = M2 V2 Vi = M,Ve - 0.10() xIL Vi =? Me = 0.10M V2 = IL Mi Vi = 0.01aelaleL V= le.67 mL v A student titrates a 25.00 mL aliquot of HCl (concentration unknown) with 33.10 mL of 0.1500 M NaOH. What is the concentration of HCI? Show caļculation with units. HCl + Na DH -> H,0 + NaCí Given: MiV. M2 V2 Mi= use MVi= Mi= 0.190&M M2V2 Concentration of Hel=0.1904M you cannot VI 25 x 10-L MI=! VI = 25 mL Ma= 0.15,00M Vz = 38.10 mL=39.10x|ID L 3.
Transcribed Image Text:2. What is the mass of KHP that you will weigh? 700-807m9 aThe instructions read "Weigh out accurately 700 to 800 tng of KHP". Why are you given a range in the instructions and why is this acceptable? It is acceptable because KH P is the excess reactaint dnd theref ure, you only need to haye enough. moles of this compound but speritic not a spečific number or mole's. Why is it important to not have any bubbles in the tip of the buret? ubles inthe tip It is, ivmeortaut not to have of the outet becawe, ot hervyise, the yolvune of fit raut actuaily Added will Sof titrant that can be written acording to the buret. If there are bubbles in the tip ofuthe buret, the volume of titrant that, actvally cts in contact with the analyte, will be lower trad thie recorded Any dif ferent from the yolume volume. How 4. many milliliters of 6.0 M NAOH must be used to prepare 1.0 L of 0.10 M NaOH? Show calculation with units. Given: MiV, = M2 V2 Vi = M,Ve - 0.10() xIL Vi =? Me = 0.10M V2 = IL Mi Vi = 0.01aelaleL V= le.67 mL v A student titrates a 25.00 mL aliquot of HCl (concentration unknown) with 33.10 mL of 0.1500 M NaOH. What is the concentration of HCI? Show caļculation with units. HCl + Na DH -> H,0 + NaCí Given: MiV. M2 V2 Mi= use MVi= Mi= 0.190&M M2V2 Concentration of Hel=0.1904M you cannot VI 25 x 10-L MI=! VI = 25 mL Ma= 0.15,00M Vz = 38.10 mL=39.10x|ID L 3.
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