4.35 L He/1 x 1 mole He/22.4 L He. When we solve this problem we get 0.19419642. Apply the significant figure rules to the final answer. Then explain why the final answer makes sense using the example answer attached to help.
4.35 L He/1 x 1 mole He/22.4 L He. When we solve this problem we get 0.19419642. Apply the significant figure rules to the final answer. Then explain why the final answer makes sense using the example answer attached to help.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
100%
4.35 L He/1 x 1 mole He/22.4 L He.
When we solve this problem we get 0.19419642. Apply the significant figure rules to the final answer.
Then explain why the final answer makes sense using the example answer attached to help.

Transcribed Image Text:01 ▶▶
02
03 >>
04 >>
05 >>
Significant Figure Rules
Rules
All nonzero digits are significant.
Zeros that appear between other
nonzero digits are always significant.
Zeros that appear in front of all of the
nonzero digits are called left-end zeros.
Left-end zeros are never significant.
Zeros that appear after all nonzero
digits are called right-end zeros.
Right-end zeros in a number that lacks
a decimal point are not significant.
Right-end zeros in a number with a
decimal point are significant.
This is true whether the zeros occur
before or after the decimal point.
237 has three significant figures.
1.897 has four significant figures.
39,004 has five significant figures.
5.02 has three significant figures.
0.008 has one significant figure.
0.000416 has three significant figures.
140 has two significant figures.
75,210 has four significant Ligures.
620.0 has four significant figures.
19.000 has five significant figures.
For multiplication and division problems, the answer should be
rounded to the same number of significant figures as the
measurement with the least number of significant figures.

Transcribed Image Text:Step 2: Calculate.
24 hr
1 d
1dx
X
60 min
1 hr
X
60 s
1 min
86, 400 s
%D
Applying the first conversion factor, the "d"
unit cancels and 1 × 24 = 24. Applying the
second conversion factor, the "hr" unit
cancels and 24 × 60 = 1440. Applying the
third conversion factor, the "min" unit cancels
and 1440 × 60 = 86, 400. The unit that remains
is "s" for seconds.
Step 3: Think about your result.
Seconds is a much smaller unit of time than
days, so it makes sense that there are a very
large number of seconds in one day.
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