Need help with question 2 ONLY 2.Copyright All May not he scaned, or in or in part. Due to party may te from the eChapterrs)Editer inl review has deemed thut any nct the the to ramove al any if equare itO 2013 All May not be or or toa website, in or in part.132Experiment 6Questions1. а.NaOH + NH,C→NaCl + NH3+ H,Oh Compare your experimental value with the one you have just calculated. The correct value isonly -39 kJ/mol. Try to explain any discrepancy between the experimental and calculatedvalues and between these values and the correct value.Calculate the enthalpy change to be expected for the reactionNaCl(s) → NaCl(aq)where (s) and (aq) mean solid and aqueous, respectively. Use Hess's law, one of the threeenthalpy changes that was measured in this experiment, and the data from the following table.Reaction*AH (kJ/mol)1/2H¿(g) + 1/2C½(g) → HCl(g)-92.3Na(s) + 1/2O2(g) + 1/2H2( g) → NaOH(s)-426.8Na(s) + 1/2C12(g) – NaCl(s)-411.1-285.8HCl(g) → HCl(aq)()O'H- (3)F07/I + (8)*H-75.2NaOH($) — NaOН ад)-41.8* (g) = gas, (1) = liquid, (s) = solid, and (aq) = aqueous.%3D%3D%3DCalculations:

To find enthalpy change of the below reaction. NaCl(s) → NaCl(aq)According to the Hess’s law, the enthalpy change in a reaction is independent of the path taken and is the sum of the enthalpy change in each individual step that is used in the process.Re-writing each step 1/2H2g+1/2Cl2g→HClgNas+1/2O2g+1/2H2g→NaOHsNaCls→Nas+1/2Cl2gH2Ol→H2g+1/2O2gHClg→HClaqNaOHs→NaOHaqΔ1H=−92.3 KJ/molΔ2H=−426.8 KJ/molΔ3H=+411.1 KJ/molΔ4H=+285.8 KJ/molΔ5H=−75.2 KJ/molΔ6H=−41.8 KJ/molFor the final reaction, add enthalpies of each step. Reaction: NaCls+H2Ol→NaOHaq+HClaq ΔH=ΔH1+ΔH2+ΔH3+ΔH4+ΔH5+ΔH6ΔH=−92.3 KJ/mol+−426.8 KJ/mol+411.1 KJ/mol+285.8 KJ/mol+−75.2 KJ/mol+−47.8 KJ/molΔH=60.8 KJ/molBelow reaction step is missing in the table NaOHaq+HClaq→NaClaq+H2Ol ; ΔH=−56.9 KJ/molNow add both the reaction, it gives NaCls→NaClaqΔH=60.8 KJ/mol−56.9 KJ/mol=3.9 KJ/molThus, the enthalpy change is 3.9 KJ/mol

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2. Calculate the enthalpy change to be expected for the reaction NaCl(s) → NaCl(aq) where (s) and (aq) mean solid and aqueous, respectively. Use Hess's law, one of the three enthalpy changes that was measured in this experiment, and the data from the following table. Reaction* AH (kJ/mol) 1/2H;(g) + 1/2Cl;(g) → HCl(g) -92.3 -426.8 Na(s) + 1/20:(g) + 1/2H;(g) → NaOH(s) Na(s) + 1/2Cl:(g) → NaCl(s) -285.8 HC(g) → HC(aq) -75.2 NaOH(s) –→ NaOH(aq) -41.8 * (g) - gas, (1) = liquid, (s) = solid, and (aq) = aqueous. Calculations:

2. Calculate the enthalpy change to be expected for the reaction NaCl(s) → NaCl(aq) where (s) and (aq) mean solid and aqueous, respectively. Use Hess's law, one of the three enthalpy changes that was measured in this experiment, and the data from the following table. Reaction* AH (kJ/mol) 1/2H;(g) + 1/2Cl;(g) → HCl(g) -92.3 -426.8 Na(s) + 1/20:(g) + 1/2H;(g) → NaOH(s) Na(s) + 1/2Cl:(g) → NaCl(s) -285.8 HC(g) → HC(aq) -75.2 NaOH(s) –→ NaOH(aq) -41.8 * (g) - gas, (1) = liquid, (s) = solid, and (aq) = aqueous. Calculations:

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Need help with question 2 ONLY

2.
Copyright All May not he scaned, or in or in part. Due to party may te from the eChapterrs)
Editer inl review has deemed thut any nct the the to ramove al any if equare it
O 2013 All May not be or or toa website, in or in part.
132
Experiment 6
Questions
1. а.
NaOH + NH,C→NaCl + NH3+ H,O
h Compare your experimental value with the one you have just calculated. The correct value is
only -39 kJ/mol. Try to explain any discrepancy between the experimental and calculated
values and between these values and the correct value.
Calculate the enthalpy change to be expected for the reaction
NaCl(s) → NaCl(aq)
where (s) and (aq) mean solid and aqueous, respectively. Use Hess's law, one of the three
enthalpy changes that was measured in this experiment, and the data from the following table.
Reaction*
AH (kJ/mol)
1/2H¿(g) + 1/2C½(g) → HCl(g)
-92.3
Na(s) + 1/2O2(g) + 1/2H2( g) → NaOH(s)
-426.8
Na(s) + 1/2C12(g) – NaCl(s)
-411.1
-285.8
HCl(g) → HCl(aq)
()O'H- (3)F07/I + (8)*H
-75.2
NaOH($) — NaOН ад)
-41.8
* (g) = gas, (1) = liquid, (s) = solid, and (aq) = aqueous.
%3D
%3D
%3D
Calculations:

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