Predict the ArH° 298 for the reaction: n-C6H14 (I) + CH4 (g) → n - C7H16 (1) + H2(g) Given the enthalpy of combustion, AcH° 298 (kJ mol-1) = -4,141.3, -882.0, -4,811.2 and -286.1 for n- C6H14, CH4, n - C7H16, H2, respectively.

Introduction to Chemical Engineering Thermodynamics
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Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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- 74.0 kJ
74.0 kJ
30.78 kJ
- 30.78 kJ
Transcribed Image Text:- 74.0 kJ 74.0 kJ 30.78 kJ - 30.78 kJ
Predict the ArHO 298 for the reaction: n-C6H14 (1) + CH4 (g) → n – C7H16 (1) + H2(g)
Given the enthalpy of combustion, ACH° 298 (kJ mol") = -4,141.3, -882.0, -4,811.2 and -286.1 for n-
C6H14, CH4, n- C7H16, H2, respectively.
Transcribed Image Text:Predict the ArHO 298 for the reaction: n-C6H14 (1) + CH4 (g) → n – C7H16 (1) + H2(g) Given the enthalpy of combustion, ACH° 298 (kJ mol") = -4,141.3, -882.0, -4,811.2 and -286.1 for n- C6H14, CH4, n- C7H16, H2, respectively.
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